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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Find x if distance between points L(x, 7) and M(1, 15) is 10.

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प्रश्न

Find x if distance between points L(x, 7) and M(1, 15) is 10. 

बेरीज
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उत्तर १

L(x, 7), M(1, 15), and LM = 10.

By distance formula,

∴ LM = `sqrt((x − 1)^2 + (7 − 15)^2)`

∴ 10 = `sqrt((x - 1)^2 + (− 8)^2)`

Squaring both the sides, we get,

∴ 100 = (x − 1)2 + 64

∴ (x − 1)= 100 − 64

∴ (x − 1)= 36

Taking square roots of both the sides,

∴ x − 1 = `+-` 6

∴ x − 1 = 6        or        x - 1 = −6

∴ x = 6 + 1       or        x = −6 + 1

∴ x = 7       or        x = −5

x = 7 or x = −5

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उत्तर २

L(x, 7), M(1, 15), and LM = 10.

By distance formula,

∴ LM = `sqrt((x − 1)^2 + (7 − 15)^2)`

∴ 10 = `sqrt((x - 1)^2 + (− 8)^2)`

Squaring both the sides, we get,

∴ 100 = (x − 1)2 + 64

∴ 100 = x2 − 2x + 1 + 64

∴ 100 = x2 − 2x + 65

∴ x2 − 2x + 65 − 100 = 0

∴ x2 − 2x − 35 = 0

∴ x2 − 7x + 5x - 35 = 0

∴ x(x − 7) + 5(x − 7) = 0

∴ (x − 7)(x + 5) = 0

∴ x − 7  = 0          or       x + 5 = 0  

∴ x = 7          or             x = −5

x = 7 or x = −5

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Co-ordinate Geometry - Practice Set 5.1 [पृष्ठ १०८]

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बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
पाठ 5 Co-ordinate Geometry
Practice Set 5.1 | Q 7 | पृष्ठ १०८

संबंधित प्रश्‍न

Show that the points (a, a), (–a, –a) and (– √3 a, √3 a) are the vertices of an equilateral triangle. Also find its area.


Determine if the points (1, 5), (2, 3) and (−2, −11) are collinear.


Find the point on the x-axis which is equidistant from (2, –5) and (–2, 9).


If a ≠ b ≠ 0, prove that the points (a, a2), (b, b2) (0, 0) will not be collinear.


If the distances of P(x, y) from A(5, 1) and B(–1, 5) are equal, then prove that 3x = 2y


Find the value of a when the distance between the points (3, a) and (4, 1) is `sqrt10`


Find the centre of the circle passing through (6, -6), (3, -7) and (3, 3)


Find the distance between the points `A((-8)/5, 2)` and `B(2/5, 2)`.


Show that the points A(1, 2), B(1, 6), C(1 + 2`sqrt3`, 4) are vertices of an equilateral triangle.


Find the distance of a point (13 , -9) from another point on the line y = 0 whose abscissa is 1.


Prove that the following set of point is collinear :

(4, -5),(1 , 1),(-2 , 7)


Find the coordinate of O , the centre of a circle passing through P (3 , 0), Q (2 , `sqrt 5`) and R (`-2 sqrt 2` , -1). Also find its radius.


Find the distance between the origin and the point:
(8, −15)


Show that (-3, 2), (-5, -5), (2, -3) and (4, 4) are the vertices of a rhombus.


Find the distance of the following points from origin.
(a cos θ, a sin θ).


The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = ______.


Show that the points (0, –1), (8, 3), (6, 7) and (–2, 3) are vertices of a rectangle.


If the distance between the points (x, -1) and (3, 2) is 5, then the value of x is ______.


Case Study -2

A hockey field is the playing surface for the game of hockey. Historically, the game was played on natural turf (grass) but nowadays it is predominantly played on an artificial turf.

It is rectangular in shape - 100 yards by 60 yards. Goals consist of two upright posts placed equidistant from the centre of the backline, joined at the top by a horizontal crossbar. The inner edges of the posts must be 3.66 metres (4 yards) apart, and the lower edge of the crossbar must be 2.14 metres (7 feet) above the ground.

Each team plays with 11 players on the field during the game including the goalie. Positions you might play include -

  • Forward: As shown by players A, B, C and D.
  • Midfielders: As shown by players E, F and G.
  • Fullbacks: As shown by players H, I and J.
  • Goalie: As shown by player K.

Using the picture of a hockey field below, answer the questions that follow:

If a player P needs to be at equal distances from A and G, such that A, P and G are in straight line, then position of P will be given by ______.


A circle has its centre at the origin and a point P(5, 0) lies on it. The point Q(6, 8) lies outside the circle.


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