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प्रश्न
Find the distance between the following point :
(sin θ , cos θ) and (cos θ , - sin θ)
योग
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उत्तर
A (sin θ , cos θ) , B (cos θ , - sin θ)
AB = `sqrt (("cos" theta - "sin" theta )^2 (- "sin" θ - "cos " θ)^2)`
`= sqrt ("cos"^2 θ + "sin"^2 θ - 2 "cos" θ "sin" θ + "sin"^2 theta + "cos"^2 theta + 2 "cos" theta "sin" theta) `
`= sqrt 2` units
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