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Find a point which is equidistant from the points A(–5, 4) and B(–1, 6)? How many such points are there?

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प्रश्न

Find a point which is equidistant from the points A(–5, 4) and B(–1, 6)? How many such points are there?

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उत्तर

Let P(h, k) be the point which is equidistant from the points A(–5, 4) and B(–1, 6).

∴ PA = PB   ...`[∵ "By distance formula, distance" = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)]`

⇒ (PA)2 = (PB)2

⇒ (– 5 – h)2 + (4 – k)2 = (– 1 – h)2 + (6 – k)2

⇒ 25 + h2 + 10h + 16 + k2 – 8k = 1 + h2 + 2h + 36 + k2 – 12k

⇒ 25 + 10h + 16 – 8k = 1 + 2h + 36 – 12k

⇒ 8h + 4k + 41 – 37 = 0

⇒ 8h + 4k + 4 = 0

⇒ 2h + k + 1 = 0   ...(i)

Mid-point of AB = `((-5 - 1)/2, (4 + 6)/2)` = (– 3, 5)   ...`[∵ "Mid-point" = ((x_1 + x_2)/2, (y_1 + y_2)/2)]`

At point (– 3, 5), from equation (i),

2h + k = 2(– 3) + 5

= – 6 + 5

= – 1

⇒ 2h + k + 1 = 0

So, the mid-point of AB satisfy the equation (i).

Hence, infinite number of points, in fact all points which are solution of the equation 2h + k + 1 = 0, are equidistant from the points A and B.

Replacing h, k by x, y in above equation, we have 2x + y + 1 = 0

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अध्याय 7: Coordinate Geometry - Exercise 7.3 [पृष्ठ ८३]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 10
अध्याय 7 Coordinate Geometry
Exercise 7.3 | Q 5 | पृष्ठ ८३

वीडियो ट्यूटोरियलVIEW ALL [1]

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Using distance formula, find which of them is correct.


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x1 = 3, y1 = –7 and x2 = 3, y2 = 3

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Case Study -2

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Alia and Shagun are friends living on the same street in Patel Nagar. Shagun's house is at the intersection of one street with another street on which there is a library. They both study in the same school and that is not far from Shagun's house. Suppose the school is situated at the point O, i.e., the origin, Alia's house is at A. Shagun's house is at B and library is at C.

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