Advertisements
Advertisements
प्रश्न
Find the distance of the following points from the origin:
(i) A(5,- 12)
Advertisements
उत्तर
A(5,- 12)
Let O(0,0) be the origin
`OA = sqrt((5-0)^2 +(-12 - 0)^2)`
`= sqrt((5)^2 +(-12)^2)`
`=sqrt(25+144)`
`=sqrt(169)`
=13 units
APPEARS IN
संबंधित प्रश्न
Find the distance between the following pairs of points:
(2, 3), (4, 1)
Name the type of quadrilateral formed, if any, by the following point, and give reasons for your answer:
(4, 5), (7, 6), (4, 3), (1, 2)
Find the distance between the following pair of points:
(a+b, b+c) and (a-b, c-b)
Find the values of x, y if the distances of the point (x, y) from (-3, 0) as well as from (3, 0) are 4.
Find the distances between the following point.
P(–6, –3), Q(–1, 9)
If the point P(2, 1) lies on the line segment joining points A(4, 2) and B(8, 4), then ______.
Find the value of a if the distance between the points (5 , a) and (1 , 5) is 5 units .
Find the relation between x and y if the point M (x,y) is equidistant from R (0,9) and T (14 , 11).
Find the point on y-axis whose distances from the points A (6, 7) and B (4, -3) are in the ratio 1: 2.
The points A (3, 0), B (a, -2) and C (4, -1) are the vertices of triangle ABC right angled at vertex A. Find the value of a.
KM is a straight line of 13 units If K has the coordinate (2, 5) and M has the coordinates (x, – 7) find the possible value of x.
If the point (x, y) is at equidistant from the point (a + b, b – a) and (a-b, a + b). Prove that ay = bx.
Find distance between point A(– 3, 4) and origin O
Find distance between point A(7, 5) and B(2, 5)
Find distance of point A(6, 8) from origin
Show that P(– 2, 2), Q(2, 2) and R(2, 7) are vertices of a right angled triangle
Show that the points (2, 0), (– 2, 0) and (0, 2) are vertices of a triangle. State the type of triangle with reason
Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).
Name the type of triangle formed by the points A(–5, 6), B(–4, –2) and C(7, 5).
Find distance between points P(– 5, – 7) and Q(0, 3).
By distance formula,
PQ = `sqrt(square + (y_2 - y_1)^2`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(square + square)`
= `sqrt(125)`
= `5sqrt(5)`
