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Point P(0, 2) is the point of intersection of y–axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3). - Mathematics

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प्रश्न

Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).

विकल्प

  • True

  • False

MCQ
सत्य या असत्य
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उत्तर

This statement is False.

Explanation:

We know that, the points lying on perpendicular bisector of the line segment joining the two points is equidistant from the two points.

i.e., PA should be equals to the PB.

Using distance formula,

d = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

PA = `sqrt([-4 - (4)]^2 + (6 - 2)^2`

PA = `sqrt((0)^2 + (4)^2` = 4

PB = `sqrt([-4 - 4]^2 + (-6 - 2)^2`

PB = `sqrt(0^2 + (-8)^2` = 8

∵ PA ≠ PB

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अध्याय 7: Coordinate Geometry - Exercise 7.2 [पृष्ठ ८१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 7 Coordinate Geometry
Exercise 7.2 | Q 4 | पृष्ठ ८१

वीडियो ट्यूटोरियलVIEW ALL [1]

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