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Point P(0, 2) is the point of intersection of y–axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).

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Question

Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is False.

Explanation:

We know that, the points lying on perpendicular bisector of the line segment joining the two points is equidistant from the two points.

i.e., PA should be equals to the PB.

Using distance formula,

d = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

PA = `sqrt([-4 - (4)]^2 + (6 - 2)^2`

PA = `sqrt((0)^2 + (4)^2` = 4

PB = `sqrt([-4 - 4]^2 + (-6 - 2)^2`

PB = `sqrt(0^2 + (-8)^2` = 8

∵ PA ≠ PB

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Chapter 7: Coordinate Geometry - Exercise 7.2 [Page 81]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 10
Chapter 7 Coordinate Geometry
Exercise 7.2 | Q 4 | Page 81
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