हिंदी

Show that points A(–1, –1), B(0, 1), C(1, 3) are collinear.

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प्रश्न

Show that points A(–1, –1), B(0, 1), C(1, 3) are collinear.

योग
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उत्तर १

A(–1, –1), B(0, 1), C(1, 3)

AB = `sqrt((0 + 1)^2 + (1 + 1)^2`

= `sqrt(1 + 4)`

AB = `sqrt(5)`

BC = `sqrt((1)^2 + (2)^2`

= `sqrt(1 + 4)`

BC = `sqrt(5)`

AC = `sqrt((2)^2 + (3 + 1)^2`

= `sqrt(4 + 16)`

= `sqrt(20)`

= `sqrt(5 xx 4)`

AC = `2sqrt(5)`

AB + BC = AC

`sqrt(5) + sqrt(5) = 2sqrt(5)`

A, B, and C are collinear.

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उत्तर २

A`(x_1, y_1) = (-1, -1)`
B`(x_2, y_2) = (0,1)`
C`(x_3, y_3) = (1, 3)`

Slope of line
AB = `(y_2 - y_1)/(x_2 - x_1)`

      = `(1 - (-1))/(0 - (-1))`

      = `(1+1)/1 = 2`

Slope of line
BC = `(y_3 - y_2)/(x_3 - x_2)`

      = `(3 - 1)/(1 - 0)`

      = `2/1 = 2.`

As, slope of line AB = slope of line BC
Also AB and BC Hrtes contain common point B

∴ Points A, B, C are collinear.                   Hence Proved

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