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In a circle with centre at point O, chord AB is a side of a square and chord BC is a side of regular hexagon. Then angle AOC is equal to ______.

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Question

In a circle with centre at point O, chord AB is a side of a square and chord BC is a side of regular hexagon. Then angle AOC is equal to ______.

Options

  • 120°

  • 150°

  • 90°

  • none of these

MCQ
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Solution

In a circle with centre at point O, chord AB is a side of a square and chord BC is a side of regular hexagon. Then angle AOC is equal to 150°.

Explanation:
  • Since chord AB is a side of an inscribed square, it subtends a central angle ∠AOB equal to one-fourth of a full circle:
    `\angle AOB = \frac{360^\circ}{4} = 90^\circ`
  • Since chord BC is a side of an inscribed regular hexagon, it subtends a central angle ∠BOC equal to one-sixth of a full circle:
    `\angle BOC = \frac{360^\circ}{6} = 60^\circ`
  • The total central angle ∠AOC is the sum of these two adjacent central angles:
    ∠AOC = ∠AOB + ∠BOC
    = 90° + 60°
    = 150°
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Chapter 16: Circle - TEST YOURSELF [Page 245]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 16 Circle
TEST YOURSELF | Q 1. (a) | Page 245
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