Question

In a circle of radius 17 cm, two parallel chords of lengths 30 cm and 16 cm are drawn. Find the distance between the chords, if both the chords are:

1. on the opposite sides of the centre;
2. on the same side of the centre.

Answer 1

Let O be the center of the circle and AB and CD be the two parallel chords of length 30 cm and 16 cm respectively.

Drop OE and OF perpendicular on AB and CD from the center O.

OE ⊥ AB and OF ⊥ CD.

∴ OE bisects AB and OF bisects CD.     ...(Perpendicular is drawn from the centre of a circle to a chord bisects it.)

⇒ AE = `30/2` = 15 cm;

CF = `16/2` = 8 cm

In right ΔOAE,

OA² = OE² + AE²

⇒ OE² = OA² − AE² = 17² − 15² = 64

∴ OE = 8 cm

In right ΔOCF,

OC² = OF² + CF²

⇒ OF² = OC² − CF² = 17² − 8² = 225

∴ OF = 15 cm

(i) The chord are on the opposite sides of the centre:

∴ EF = EO + OF = 8 + 15 = 23cm

(ii) The chord are on the same side of the centre:

∴ EF = OF − OE = 15 − 8 = 7 cm.