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In a circle, O is its centre and AB, CD are B its two chords. If AB : CD = 3 : 2, then ratio between ∠AOB and ∠COD is ______.

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Question

In a circle, O is its centre and AB, CD are B its two chords. If AB : CD = 3 : 2, then ratio between ∠AOB and ∠COD is ______.

Options

  • 1 : 1

  • 3 : 2

  • 2 : 5

  • 3 : 5

MCQ
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Solution

In a circle, O is its centre and AB, CD are B its two chords. If AB : CD = 3 : 2, then ratio between ∠AOB and ∠COD is 3 : 2.

Explanation:
  • In a circle, equal chords subtend equal angles at the centre, and the central angles are proportional to the lengths of their corresponding chords.
  • Given that the ratio of the chord lengths is AB : CD = 3 : 2, the ratio of the angles subtended by them at the centre, ∠AOB : ∠COD, is directly proportional to their lengths.
Therefore, the ratio between ∠AOB and ∠COD is 3 : 2.
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Chapter 16: Circle - Exercise 16(B) [Page 244]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 16 Circle
Exercise 16(B) | Q 1. (c) | Page 244
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