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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 11 - Mid-point Theorem and Its Converse [Including Intercept Theorem] [Latest edition]

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Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 11 - Mid-point Theorem and Its Converse [Including Intercept Theorem] - Shaalaa.com
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Solutions for Chapter 11: Mid-point Theorem and Its Converse [Including Intercept Theorem]

Below listed, you can find solutions for Chapter 11 of CISCE Selina for Concise Mathematics [English] Class 9 ICSE.


Exercise 11 (A)Exercise 11 (B)TEST YOURSELF
Exercise 11 (A) [Pages 168 - 169]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 11 Mid-point Theorem and Its Converse [Including Intercept Theorem] Exercise 11 (A) [Pages 168 - 169]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 168

In the given figure, ABCD is a rectangle. As per the given information, the length of PQ is:

  • 12 cm

  • 14 cm

  • 20 cm

  • 10 cm

1. (b)Page 168

The quadrilateral obtained by joining the mid-points (in order) of the sides of quadrilateral ABCD is a ______.

  • rectangle

  • rhombus

  • parallelogram

  • square

1. (c)Page 168

If BC = 12 cm, AB = 14.8 cm. AC = 12.8 cm, the perimeter of quadrilateral BCYX is ______.

  • 31.8 cm

  • 15.9 cm

  • 29.8 cm

  • 32.8 cm

1. (d)Page 168

In the given figure, AB = AC, P, Q and R are mid-points of sides BC, CA and AB, respectively, then ΔPQR is ______.

  • scalene

  • isosceles

  • equilateral

  • obtuse angled

1. (e)Page 168

P, Q, R and S are the midpoints of sides AB, BС, CD and DA, respectively, of rectangle ABCD; then quadrilateral PQRS is a ______.

  • rectangle

  • rhombus

  • square

  • parallelogram

2.Page 168

In triangle ABC, M is mid-point of AB and a straight line through M and parallel to BC cuts AC in N. Find the lengths of AN and MN if Bc = 7 cm and Ac = 5 cm.

3.Page 168

Prove that the figure obtained by joining the mid-points of the adjacent sides of a rectangle is a rhombus.

4.Page 168

D, E, and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC.

Prove that ΔDEF is also isosceles.

5.Page 168

The following figure shows a trapezium ABCD in which AB // DC. P is the mid-point of AD and PR // AB. Prove that:

PR = `[1]/[2]` ( AB + CD)

6.Page 168

The figure, given below, shows a trapezium ABCD. M and N are the mid-point of the non-parallel sides AD and BC respectively. Find: 

  1. MN, if AB = 11 cm and DC = 8 cm.
  2. AB, if DC = 20 cm and MN = 27 cm.
  3. DC, if MN = 15 cm and AB = 23 cm.
7.Page 169

The diagonals of a quadrilateral intersect at right angles. Prove that the figure obtained by joining the mid-points of the adjacent sides of the quadrilateral is rectangle.

8.Page 169

L and M are the mid-point of sides AB and DC respectively of parallelogram ABCD. Prove that segments DL and BM trisect diagonal AC.

9.Page 169

ABCD is a quadrilateral in which AD = BC. E, F, G and H are the mid-points of AB, BD, CD and Ac respectively. Prove that EFGH is a rhombus.

10.Page 169

A parallelogram ABCD has P the mid-point of Dc and Q a point of Ac such that

CQ = `[1]/[4]`AC. PQ produced meets BC at R.

Prove that
(i)R is the midpoint of BC
(ii) PR = `[1]/[2]` DB

Exercise 11 (B) [Pages 171 - 172]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 11 Mid-point Theorem and Its Converse [Including Intercept Theorem] Exercise 11 (B) [Pages 171 - 172]

Multiple Choice Tуре: Choose the correct answer from the options given below.

1. (a)Page 171

In the given figure, l // m // n and D is mid-point of CE. If AE = 12.6 cm, then BD is ______.

  • 12.6 cm

  • 25.2 cm

  • 6.3 cm

  • 18.9 cm

1. (b)Page 171

In a trapezium ABCD, AB//DC, E is midpoint of AD and F is mid-point of BC, then:

  • 2EF = `1/2` (AB + DC)

  • 2EF = AB + DC

  • EF = AB + DC

  • EF = `1/2` × AB × DC

1. (c)Page 171

The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL//EB. Then, BF is equal to:

  • AD

  • BE

  • AE

  • AB

1. (d)Page 171

In the given figure, AD and BE are medians; then ED is equal to:

  • 2AB

  • `1/2` AB

  • `1/4` AB

  • `1/8` AB

1. (e)Page 172

In the quadrilateral ABCD, if AB//CD, E is mid-point of side AD, and F is mid-point of BC. If AB = 20 cm and EF = 16 cm, the length of side DC is:

  • 18 cm

  • 12 cm

  • 24 cm

  • 32 cm

2.Page 172

Use the following figure to find:
(i) BC, if AB = 7.2 cm.
(ii) GE, if FE = 4 cm.
(iii) AE, if BD = 4.1 cm
(iv) DF, if CG = 11 cm.

3.Page 172

In the figure, give below, 2AD = AB, P is mid-point of AB, Q is mid-point of DR and PR // BS. Prove that:
(i) AQ // BS
(ii) DS = 3 Rs.

4.Page 172

The side AC of a triangle ABC is produced to point E so that CE = AC. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meet AC at point P and EF at point R respectively.

Prove that:

  1. 3DF = EF
  2. 4CR = AB
5.Page 172

In triangle ABC, the medians BP and CQ are produced up to points M and N respectively such that BP = PM and CQ = QN. Prove that:

  1. M, A, and N are collinear.
  2. A is the mid-point of MN.
6.Page 172

In triangle ABC, angle B is obtuse. D and E are mid-points of sides AB and BC respectively and F is a point on side AC such that EF is parallel to AB. Show that BEFD is a parallelogram.

7.Page 172

In parallelogram ABCD, E and F are mid-points of the sides AB and CD respectively. The line segments AF and BF meet the line segments ED and EC at points G and H respectively.
Prove that:
(i) Triangles HEB and FHC are congruent;
(ii) GEHF is a parallelogram.

8.Page 172

In triangle ABC, D and E are points on side AB such that AD = DE = EB. Through D and E, lines are drawn parallel to BC which meet side AC at points F and G respectively. Through F and G, lines are drawn parallel to AB which meets side BC at points M and N respectively. Prove that: BM = MN = NC.

9.Page 172

In triangle ABC; M is mid-point of AB, N is mid-point of AC and D is any point in base BC. Use the intercept Theorem to show that MN bisects AD.

10.Page 172

If the quadrilateral formed by joining the mid-points of the adjacent sides of quadrilateral ABCD is a rectangle,
show that the diagonals AC and BD intersect at the right angle.

TEST YOURSELF [Pages 172 - 174]

Selina solutions for Concise Mathematics [English] Class 9 ICSE 11 Mid-point Theorem and Its Converse [Including Intercept Theorem] TEST YOURSELF [Pages 172 - 174]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 172

The mid-points of the sides of a triangle are joined together to get four triangles. These four triangles are ______.

  • not equal to each other.

  • congruent to each other.

  • not congruent to each other.

  • none of these

1. (b)Page 172

In the given figure, AB//CD//EF. If AC = 7 cm, AE = 14 cm and BF = 20 cm. then DF is equal to:

  • 7 cm

  • 14 cm

  • 10 cm

  • 16 cm

1. (c)Page 173

In the given figure, AB//DC//EF and E is mid-point of side AD, then:

  • OE : OF = 11 : 3

  • OE = OF

  • OF = 2 × OE

  • CF = FB

1. (d)Page 173

In rhombus PQRS, A, B and C are midpoints of sides PQ. QR and RS, respectively. If ∠P = 60°, the angle PQR is equal to:

  • 60°

  • 90°

  • 120°

  • none of these

1. (e)Page 173

Statement (1): The diagonals of a quadrilateral are perpendicular to each other; P, Q, R and S are mid-points of sides AB, BC, CD and DA, respectively. Then PQRS will be a rectangle.

Statement (2): Quadrilateral PQRS will be a square as each of its angles will be 90°.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (f)Page 173

Statement (1): AD is median of triangle ABC and DE is parallel to BA. Then DE will bisect AC.

Statement (2): DE is the median of ΔADC.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (g)Page 173

Assertion (A): The figure formed by joining the midpoints of the sides of a quadrilateral ABCD is a square.

Reason (R): Diagonals of the quadrilateral ABCD are not given to be equal and perpendicular to each other.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true, and R is the correct reason for A.

  • Both A and R are true, and R is the incorrect reason for A.

1. (h)Page 173

Assertion (A): R, S, D and E are midpoints of OС, ОВ, АВ, and AC, respectively; then DERS is a parallelogram.

Reason (R): DS//AO//ER and DS = ER = `1/2` AO.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true, and R is the correct reason for A.

  • Both A and R are true, and R is the incorrect reason for A.

2.Page 173

In triangle ABC, D and E are mid-points of the sides AB and AC, respectively. Through E, a straight line is drawn parallel to AB to meet BC at F. Prove that BDEF is a parallelogram. If AB = 8 cm and BC = 9 cm, find the perimeter of the parallelogram BDEF.

3.Page 173

P, Q and R are mid-points of sides AВ, ВС and CD, respectively, of a rhombus ABCD. Show that PQ is perpendicular to QR.

4.Page 173

The diagonals of a quadrilateral ABCD are perpendicular to each other. Prove that the quadrilateral obtained by joining the midpoints of its adjacent sides is a rectangle.

5.Page 174

In ∆ABC, E is the mid-point of the median AD, and BE produced meets side AC at point Q.

Show that BE: EQ = 3: 1.

6.Page 174

In the given figure, M is mid-point of AB and DE, whereas N is mid-point of BC and DF.
Show that: EF = AC.

7.Page 174

In triangle ABC, D and E are the mid-points of the sides AB and AC, respectively. Through E, a straight line is drawn parallel to AB to meet BC at F. Prove that BDEF is a parallelogram. If AB = 16 cm, AC = 12 cm and BC = 18 cm, find the perimeter of the parallelogram BDEF.

8.Page 174

In the given figure, AD and CE are medians and DF // CE.
Prove that: FB = `1/4` AB.

9.Page 174

In parallelogram ABCD, E is the mid-point of AB and AP is parallel to EC which meets DC at point O and BC produced at P.
Prove that:
(i) BP = 2AD
(ii) O is the mid-point of AP.

10.Page 174

In trapezium ABCD, sides AB and DC are parallel to each other. E is mid-point of AD and F is mid-point of BC.
Prove that: AB + DC = 2EF.

11.Page 174

In Δ ABC, AD is the median and DE is parallel to BA, where E is a point in AC. Prove that BE is also a median.

12.Page 174

Adjacent sides of a parallelogram are equal and one of the diagonals is equal to any one of the sides of this parallelogram. Show that its diagonals are in ratio √3:1.

Case-Study Based Question

1.Page 174

A school is designing a triangular garden ΔАВС. То construct a walking path inside the garden, the gardener marks the mid-points of two sides: point D is the mid-point of side AB and point E is the mid-point of side AC. The path DE is drawn to connect these mid-points. The length of side BC of the triangular garden is 12 m. AB = 10 m and AC = 10 m.

Based on the above information, answer the following:

  1. What is the length of path DЕ?
  2. Assign a special name to Quadrilateral BCED and find its perimeter.

Solutions for 11: Mid-point Theorem and Its Converse [Including Intercept Theorem]

Exercise 11 (A)Exercise 11 (B)TEST YOURSELF
Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 11 - Mid-point Theorem and Its Converse [Including Intercept Theorem] - Shaalaa.com

Selina solutions for Concise Mathematics [English] Class 9 ICSE chapter 11 - Mid-point Theorem and Its Converse [Including Intercept Theorem]

Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 9 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE 11 (Mid-point Theorem and Its Converse [Including Intercept Theorem]) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Concise Mathematics [English] Class 9 ICSE chapter 11 Mid-point Theorem and Its Converse [Including Intercept Theorem] are .

Using Selina Concise Mathematics [English] Class 9 ICSE solutions Mid-point Theorem and Its Converse [Including Intercept Theorem] exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 9 ICSE students prefer Selina Textbook Solutions to score more in exams.

Get the free view of Chapter 11, Mid-point Theorem and Its Converse [Including Intercept Theorem] Concise Mathematics [English] Class 9 ICSE additional questions for Mathematics Concise Mathematics [English] Class 9 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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