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In a trapezium ABCD, AB//DC, E is midpoint of AD and F is mid-point of BC, then:

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Question

In a trapezium ABCD, AB//DC, E is midpoint of AD and F is mid-point of BC, then:

Options

  • 2EF = `1/2` (AB + DC)

  • 2EF = AB + DC

  • EF = AB + DC

  • EF = `1/2` × AB × DC

MCQ
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Solution

2EF = AB + DC

Explanation:

By the properties of a trapezium, the line segment joining the midpoints of the non-parallel sides is equal to half the sum of the parallel sides (EF = `1/2`(AB + DC)). Multiplying both sides by 2 yields the relation 2EF = AB + DC.

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Chapter 11: Mid-point Theorem and Its Converse [Including Intercept Theorem] - Exercise 11 (B) [Page 171]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 11 Mid-point Theorem and Its Converse [Including Intercept Theorem]
Exercise 11 (B) | Q 1. (b) | Page 171
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