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Question
In a trapezium ABCD, AB//DC, E is midpoint of AD and F is mid-point of BC, then:
Options
2EF = `1/2` (AB + DC)
2EF = AB + DC
EF = AB + DC
EF = `1/2` × AB × DC
MCQ
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Solution
2EF = AB + DC
Explanation:
By the properties of a trapezium, the line segment joining the midpoints of the non-parallel sides is equal to half the sum of the parallel sides (EF = `1/2`(AB + DC)). Multiplying both sides by 2 yields the relation 2EF = AB + DC.
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