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The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL//EB. Then, BF is equal to:

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Question

The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL//EB. Then, BF is equal to:

Options

  • AD

  • BE

  • AE

  • AB

MCQ
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Solution

AB

Explanation:

By applying the Intercept Theorem, since E is the midpoint of AD and DL || EB, L is the midpoint of CB. Triangles BLF and DLC are congruent by the ASA criterion, giving BF = CD; since opposite sides of a parallelogram are equal (CD = AB), it follows that BF = AB.

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Chapter 11: Mid-point Theorem and Its Converse [Including Intercept Theorem] - Exercise 11 (B) [Page 171]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 11 Mid-point Theorem and Its Converse [Including Intercept Theorem]
Exercise 11 (B) | Q 1. (c) | Page 171
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