Question

In a trapezium ABCD, AB//DC, E is midpoint of AD and F is mid-point of BC, then:

विकल्प

• 2EF = `1/2` (AB + DC)

• 2EF = AB + DC

• EF = AB + DC

• EF = `1/2` × AB × DC

Answer 1

2EF = AB + DC

Explanation:

By the properties of a trapezium, the line segment joining the midpoints of the non-parallel sides is equal to half the sum of the parallel sides (EF = `1/2`(AB + DC)). Multiplying both sides by 2 yields the relation 2EF = AB + DC.