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In the given figure, AB//CD//EF. If AC = 7 cm, AE = 14 cm and BF = 20 cm. then DF is equal to:

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Question

In the given figure, AB//CD//EF. If AC = 7 cm, AE = 14 cm and BF = 20 cm. then DF is equal to:

Options

  • 7 cm

  • 14 cm

  • 10 cm

  • 16 cm

MCQ
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Solution

10 cm

Explanation:

By the Intercept Theorem, parallel lines divide transversals proportionally, so `{AC}/{CE} = {BD}/{DF}`. Given AC = 7 cm and AE = 14 cm, C is the midpoint of AE, which means BD = DF. Therefore, DF is half of the total length of BF (20 cm), so DF = 10 cm.

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Chapter 11: Mid-point Theorem and Its Converse [Including Intercept Theorem] - TEST YOURSELF [Page 172]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 11 Mid-point Theorem and Its Converse [Including Intercept Theorem]
TEST YOURSELF | Q 1. (b) | Page 172
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