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Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 11 - Geometric Progression [Latest edition]

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Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 11 - Geometric Progression - Shaalaa.com
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Solutions for Chapter 11: Geometric Progression

Below listed, you can find solutions for Chapter 11 of CISCE Selina for Concise Mathematics [English] Class 10 ICSE.


Exercise 11 (A)Exercise 11 (B)TEST YOURSELF
Exercise 11 (A) [Pages 150 - 151]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 11 Geometric Progression Exercise 11 (A) [Pages 150 - 151]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 150

If the first term of a G.P. is 8 and its common ratio is −2 . The 3rd term of this G.P. is ______.

  • −32

  • 2

  • 32

  • −2

1. (b)Page 150

The 4th term of a G.P. is 16 and the 7th term is 128, then its common ratio is equal to ______.

  • 2

  • −2

  • 1

  • −1

1. (c)Page 150

(2x + 2) and (3x + 3) are two consecutive terms of a G.P. The common ratio of the GP. is ______.

  • 2

  • 3

  • \[\frac{3}{2}\]

  • \[\frac{2}{3}\]

1. (d)Page 150

The third term of a G.P. is 3. The product of its first five terms is ______.

  • 15

  • \[\frac{3 \times 5}{2}\]

  • 35

  • 53

1. (e)Page 150

The 8th term of a G.P. is 192 and its common ratio is 2, then the first term of the G.P. is ______.

  • 3

  • \[\frac{1}{3}\]

  • \[\frac{2}{3}\]

  • \[\frac{3}{2}\]

2.Page 150

Find the 9th term of the series :

1, 4, 16, 64, ...............

3.Page 150

Find the seventh term of the G.P. :

`1, sqrt(3), 3, 3sqrt(3), ............`

4.Page 151

Find the 8th term of the sequence:

`3/4, 1 1/2, 3, ..............`

5.Page 151

Find the next three terms of the sequence :

`sqrt5, 5, 5sqrt(5), .............`

6.Page 151

Find the seventh term of the G.P.:

`sqrt(3) + 1, 1, (sqrt(3) - 1)/2, .........`

7.Page 151

Find the next two terms of the series :

2 – 6 + 18 – 54 ..........

8.Page 151

Which term of the G.P.:

`-10, 5/sqrt(3), -5/6,....` is `-5/72`?

9.Page 151

The fifth term of a G.P. is 81 and its second term is 24. Find the geometric progression.

10.Page 151

Fourth and seventh terms of a G.P. are `1/18` and `-1/486` respectively. Find the G.P.

11.Page 151

If the first and the third terms of a G.P. are 2 and 8 respectively, find its second term.

12.Page 151

The product of 3rd and 8th terms of a G.P. is 243. If its 4th term is 3, find its 7th term.

13.Page 151

Find the geometric progression with 4th term = 54 and 7th term = 1458.

14.Page 151

Second term of a geometric progression is 6 and its fifth term is 9 times of its third term. Find the geometric progression. Consider that each term of the G.P. is positive.

15.Page 151

The fourth term, the seventh term and the last term of a geometric progression are 10, 80 and 2560 respectively. Find its first term, common ratio and number of terms.

16.Page 151

If the 4th and 9th terms of a G.P. are 54 and 13122 respectively, find the G.P. Also, find its general term.

17.Page 151

The fifth, eight and eleventh terms of a geometric progression are p, q and r respectively. Show that : q2 = pr.

18.Page 151

Find the seventh term from the end of the series :

`sqrt(2), 2, 2sqrt(2), ........., 32.`

19.Page 151

Find the third term from the end of the G.P.

`2/27, 2/9, 2/3, .........,162.`

20.Page 151

For the G.P. `1/27, 1/9, 1/3, ........., 81`; find the product of fourth term from the beginning and the fourth term from the end.

21.Page 151

If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that `1/x + 1/y = 2/b`

22.Page 151

If a, b and c are in A.P. and also in G.P., show that : a = b = c.

Exercise 11 (B) [Pages 154 - 155]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 11 Geometric Progression Exercise 11 (B) [Pages 154 - 155]

Multiple Choice Tyре: Choose the correct answer from the options given below.

1. (a)Page 154

The sum of first four terms of the G.P. 2, 6, 18, ....., is ______.

  • 26

  • 80

  • 160

  • 52

1. (b)Page 154

The 4th term of a G.P. is 54 and its 7th term is 1458, the common ratio of this G.P is ______.

  • `1/3`

  • 3

  • −3

  • `-1/3`

1. (c)Page 155

8, x and 32 are in GP., then the value of x is ______.

  • 24

  • 256

  • 40

  • 16

1. (d)Page 155

The sum of three terms (numbers) of a GP. is `3 1/2` and their product is 1; the numbers are ______.

  • `1/2`, 1 and 2

  • `1/3`, 3 and 9

  • 1, `1/2`, and 2

  • 2, `1/2`, and 1

1. (e)Page 155

The sum of 20 terms of the G.P. 10, 20, 40, ..... is ______.

  • `10(2^(19) - 1)`

  • `10(2^(21) - 1)`

  • `10(2^(20) - 1)`

  • none of these

2. (i)Page 155

Find the sum of G.P. :

1 + 3 + 9 + 27 + .......... to 12 terms. 

2. (ii)Page 155

Find the sum of G.P. :

0.3 + 0.03 + 0.003 + 0.0003 + ........... to 8 items.

2. (iii)Page 155

Find the sum of G.P. :

`1 - 1/2 + 1/4 - 1/8 + ..........` to 9 terms. 

3.Page 155

How many terms of the geometric progression 1 + 4 + 16 + 64 + …….. must be added to get sum equal to 5461?

4.Page 155

The first term of a G.P. is 27 and its 8th term is `1/81`. Find the sum of its first 10 terms.

5.Page 155

A boy spends Rs. 10 on first day, Rs. 20 on second day, Rs. 40 on third day and so on. Find how much, in all, will he spend in 12 days?

6.Page 155

The 4th and the 7th terms of a G.P. are `1/27` and `1/729` respectively. Find the sum of n terms of this G.P.

7.Page 155

A geometric progression has common ratio = 3 and last term = 486. If the sum of its terms is 728; find its first term.

8.Page 155

Find the sum of G.P. : 3, 6, 12, .........., 1536.

9.Page 155

How many terms of the series 2 + 6 + 18 + ............ must be taken to make the sum equal to 728?

10.Page 155

In a G.P., the ratio between the sum of first three terms and that of the first six terms is 125 : 152. Find its common ratio.

11.Page 155

If the sum of 1 + 2 + 22 + ....... + 2n – 1 is 255, find the value of n.

12.Page 155

The sum of three numbers in G.P. is `39/10` and their product is 1. Find the numbers.

13.Page 155

The first term of a G.P. is –3 and the square of the second term is equal to its 4th term. Find its 7th term.

14.Page 155

Find the 5th term of the G.P. `5/2, 1, .........`

15.Page 155

The first two terms of a G.P. are 125 and 25 respectively. Find the 5th and the 6th terms of the G.P.

16.Page 155

Find the sum of the sequence `-1/3, 1, -3, 9, ..........` upto 8 terms.

17.Page 155

The first term of a G.P. is 27 and its 8th term is `1/81`. Find the sum of its first 10 terms.

18.Page 155

Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.

TEST YOURSELF [Pages 155 - 157]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 11 Geometric Progression TEST YOURSELF [Pages 155 - 157]

1. (a)Page 155

−1, k and −1 are three consecutive terms of a G.P., then 

  1. k = 1 
  2. k = −1 

Which of the following is valid?

  • only 1

  • only 2

  • both 1 and 2

  • either 1 or −1

1. (b)Page 155

x + 9, 10 and 4 are in GP. The value of x is ______.

  • 16

  • 8

  • −16

  • 0

1. (c)Page 155

The common ratio of a G.P. is 2 and its 6th term is 48. The first term is ______.

  • `3/2`

  • `2/3`

  • 1

  • 2

1. (d)Page 155

Three terms are in G.P., whose product is 27. The middle term is ______.

  • −3

  • 3

  • −3 and 3

  • −3 or 3

1. (e)Page 156

The common ratio of a GP., whose 4th term is 27 and 6th term is 243; is ______.

  • 9

  • 3

  • `1/3`

  • `1/9`

1. (f)Page 156

The third term of a G.P. = 18, the product of its first five terms is ______.

  • 18

  • 185

  • 9

  • `sqrt18`

1. (g)Page 156

G.P.: \[\frac{2}{9}, \frac{1}{3}, \frac{1}{2}, \ldots\]. 

Assertion (A): The \[5^{\text{th}}\] term of the given G.P. is \[1\frac{1}{8}\].

Reason (R): If for a G.P., the first term is a, the common ratio is r and the number of terms is n, then the sum of the first n terms is \[S_{n}=\frac{a(r^{n}-1)}{r-1}\] for all r.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

1. (h)Page 156

For a G.P., its fourth term is x, seventh term is y and tenth term is z. 

Assertion (A): x, y and z are in G.P. 

Reason (R): \[y^{2}=(ar^{6})^{2}=ar^{3}\times ar^{9}=xz\].

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

1. (i)Page 156

Consider the G.P. 3 − 6 + 12 − 24 + ...... − 384. 

Statement (1): The product of the 5th term from the beginning and the 5th term from the end is −1152. 

Statement (2): In a G.P., the product of the nth term from the beginning and the nth term from the end is the 1st term + the last term.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

2.Page 156

The 5th and the 8th terms of a G.P. are 32 and 256 respectively. Find its first term and the common ratio.

3.Page 156

The third term of a G.P. is greater than its first term by 9 whereas its second term is greater than the fourth term by 18. Find the G.P.

4.Page 156

x, 2x + 2, 3x + 3, G are four consecutive terms of a G.P. Find the value of G.

5.Page 156

The third term of a G.P. is 2. Find the product of the first five terms of this G.P.

6.Page 156

The 10th, 16th and 22nd terms of a G.P. are x, y and z respectively. Show that x, y and z are in GP.

7.Page 156

Which term of the GP. 2, 2\[\sqrt{2}\], 4,... is 128\[\sqrt{2}\]?

8.Page 156

Find the 8th term of a GP., if its common ratio is 2 and 10th term is 768.

9.Page 156

In a G.P., the 4th term is 48 and 7th term is 384. Find its 6th term.

10.Page 156

`-5/3`, x and `(-3)/5` are three consecutive terms of a G.P. Find the value(s) of x.

11.Page 156

Rohit writes a letter to four of his friends. Hе asks each one of them to copy the letter and mail to four different persons with the instructions that they move the chain similarly. Assuming that the chain is not broken and that it costs ₹10 to mail one letter, determine the amount spent on postage when the fourth set of letters is mailed.

12.Page 156

The fourth term of a G.P. is eight times its seventh term. The fifth term of then G.P. is `3/16`, then find its 12th term.

13.Page 156

Richard borrows ₹ 10,000 from his friend Ramesh. Ramesh asks him to return the money just by repaying 10 at first day and double the amount in the subsequent days than the each previous day continuously for 10 days. Richard thanks Ramesh for his help. Determine, whether Ramesh was in loss or profit.

Case-Study Based Question:

14.Page 157

The students of a school decided to beautify the school on the Annual Day by fixing colourful flags on the straight passage of the school. A total of 27 flags have to be fixed at intervals of every 3 m. All the flags are kept at the position of the middle most flag. Rohan was given the responsibility of placing the flags on both the sides of the middle most flag. Rohan could carry only one flag at a time. So he carries one flag from the middle most point, places the flag at the designated place and comes back to the middle most point. He continues this for all the flags on both sides.

Based on the above information, answer the following questions:

  1. The distance covered by Rohan in placing the flags on one side of the middle most flag forms a sequence. Identify the type of sequence by writing at least the first 4 terms of the sequence.
  2. Find the distance covered by Rohan in placing the 10th flag and coming back to the middle most flag.
  3. Find the total distance travelled by Rohan in fixing all the 27 flags.

Solutions for 11: Geometric Progression

Exercise 11 (A)Exercise 11 (B)TEST YOURSELF
Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 11 - Geometric Progression - Shaalaa.com

Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 11 - Geometric Progression

Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 10 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 10 ICSE CISCE 11 (Geometric Progression) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Concise Mathematics [English] Class 10 ICSE chapter 11 Geometric Progression are Arithmetic Mean in A.P., Sequence, Series, and Progression, Arithmetic Progression (A.P.), General Term (nth) of an Arithmetic Progression, Sum of First ‘n’ Terms of an Arithmetic Progressions, Three or More Terms in Arithmetic Progression (A.P.), Properties of an Arithmetic Progression, Arithmetic Mean in A.P., Sequence, Series, and Progression, Arithmetic Progression (A.P.), General Term (nth) of an Arithmetic Progression, Sum of First ‘n’ Terms of an Arithmetic Progressions, Three or More Terms in Arithmetic Progression (A.P.), Properties of an Arithmetic Progression.

Using Selina Concise Mathematics [English] Class 10 ICSE solutions Geometric Progression exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 10 ICSE students prefer Selina Textbook Solutions to score more in exams.

Get the free view of Chapter 11, Geometric Progression Concise Mathematics [English] Class 10 ICSE additional questions for Mathematics Concise Mathematics [English] Class 10 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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