Question

(2x + 2) and (3x + 3) are two consecutive terms of a G.P. The common ratio of the GP. is ______.

Options

• 2

• 3

• \[\frac{3}{2}\]

• \[\frac{2}{3}\]

Answer 1

(2x + 2) and (3x + 3) are two consecutive terms of a G.P. The common ratio of the GP. is \[\frac{3}{2}\].

Explanation:

By formula,

Common ratio \[{} = \frac{a_{n \: + \: 1}}{a_n}\]

Given,

\[(2x + 2)\] and \[(3x + 3)\] are two consecutive terms of a G.P.

∴ Common ratio \[{} = \frac{3x + 3}{2x + 2}\]

\[{} = \frac{3(x + 1)}{2(x + 1)}\]

\[{} = \frac{3}{2}\]