Advertisements
Advertisements
Question
Find the 5th term of the G.P. `5/2, 1, .........`
Sum
Advertisements
Solution
First term (a) = `5/2`
And common ratio (r) = `1/(5/2) = 2/5`
Now tn = arn – 1
`=>` 5th term = t5
= `5/2 xx (5/2)^(5 - 1)`
= `5/2 xx (2/5)^4`
= `(2/5)^3`
= `8/125`
shaalaa.com
Is there an error in this question or solution?
