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प्रश्न
Find the 5th term of the G.P. `5/2, 1, .........`
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उत्तर
First term (a) = `5/2`
And common ratio (r) = `1/(5/2) = 2/5`
Now tn = arn – 1
`=>` 5th term = t5
= `5/2 xx (5/2)^(5 - 1)`
= `5/2 xx (2/5)^4`
= `(2/5)^3`
= `8/125`
संबंधित प्रश्न
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Find the 9th term of the series :
1, 4, 16, 64, ...............
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If for a G.P., pth, qth and rth terms are a, b and c respectively; prove that : (q – r) log a + (r – p) log b + (p – q) log c = 0
Q 2
If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that `a/x + c/y = 2`
If a, b and c are in A.P. and also in G.P., show that : a = b = c.
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Q 3.1
Find a G.P. for which the sum of first two terms is – 4 and the fifth term is 4 times the third term.
