Advertisements
Advertisements
प्रश्न
The first term of a G.P. is –3 and the square of the second term is equal to its 4th term. Find its 7th term.
Advertisements
उत्तर
For a G.P.
First term, a = –3
It is given that,
(2nd term)2 = 4th term
`=>` (ar)2 = ar3
`=>` a2r2 = ar3
`=>` a = r
`=>` r = –3
Now, 7th term = ar6
= –3 × (–3)6
= –3 × 729
= –2187
संबंधित प्रश्न
Find, which of the following sequence from a G.P. :
`1/8, 1/24, 1/72, 1/216, ................`
Find the 9th term of the series :
1, 4, 16, 64, ...............
Find the seventh term from the end of the series :
`sqrt(2), 2, 2sqrt(2), ........., 32.`
For the G.P. `1/27, 1/9, 1/3, ........., 81`; find the product of fourth term from the beginning and the fourth term from the end.
Q 8
Q 2
Find the sum of G.P. :
`sqrt(3) + 1/sqrt(3) + 1/(3sqrt(3)) + ..........` to n terms.
Find the geometric mean between `4/9` and `9/4`
Find the geometric mean between 2a and 8a3
Find a G.P. for which the sum of first two terms is – 4 and the fifth term is 4 times the third term.
