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प्रश्न
The first two terms of a G.P. are 125 and 25 respectively. Find the 5th and the 6th terms of the G.P.
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उत्तर
First term (a) = 125
And common ratio (r) = `25/125 = 1/5`
Now tn = arn – 1
`=>` 5th term = t5
= `125 xx (1/5)^(5 - 1)`
= `125 xx (1/5)^4`
= `125 xx 1/625`
= `1/5`
`=>` 6th term = t6
= `125 xx (1/5)^(6 - 1)`
= `125 xx (1/5)^5`
= `125 xx 1/3125`
= `1/25`
संबंधित प्रश्न
Find, which of the following sequence from a G.P. :
8, 24, 72, 216, .............
Which term of the G.P.:
`-10, 5/sqrt(3), -5/6,....` is `-5/72`?
The fifth term of a G.P. is 81 and its second term is 24. Find the geometric progression.
Find the geometric progression with 4th term = 54 and 7th term = 1458.
Find the third term from the end of the G.P.
`2/27, 2/9, 2/3, .........,162.`
For the G.P. `1/27, 1/9, 1/3, ........., 81`; find the product of fourth term from the beginning and the fourth term from the end.
Find the sum of G.P. :
1 + 3 + 9 + 27 + .......... to 12 terms.
Find the sum of G.P. :
`1 - 1/3 + 1/3^2 - 1/3^3 + .........` to n terms.
Q 2
Find the 5th term of the G.P. `5/2, 1, .........`
