Advertisements
Advertisements
प्रश्न
The first two terms of a G.P. are 125 and 25 respectively. Find the 5th and the 6th terms of the G.P.
Advertisements
उत्तर
First term (a) = 125
And common ratio (r) = `25/125 = 1/5`
Now tn = arn – 1
`=>` 5th term = t5
= `125 xx (1/5)^(5 - 1)`
= `125 xx (1/5)^4`
= `125 xx 1/625`
= `1/5`
`=>` 6th term = t6
= `125 xx (1/5)^(6 - 1)`
= `125 xx (1/5)^5`
= `125 xx 1/3125`
= `1/25`
संबंधित प्रश्न
Which term of the G.P.:
`-10, 5/sqrt(3), -5/6,....` is `-5/72`?
If the first and the third terms of a G.P. are 2 and 8 respectively, find its second term.
Find the third term from the end of the G.P.
`2/27, 2/9, 2/3, .........,162.`
If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that `a/x + c/y = 2`
Find the sum of G.P. :
`(x + y)/(x - y) + 1 + (x - y)/(x + y) + ..........` upto n terms.
Find the sum of G.P. :
`sqrt(3) + 1/sqrt(3) + 1/(3sqrt(3)) + ..........` to n terms.
Find the geometric mean between `4/9` and `9/4`
Q 2
Q 3.3
Q 8
