Question

Find the third term from the end of the G.P.

`2/27, 2/9, 2/3, .........,162.`

Answer 1

Given G.P. : `2/27, 2/9, 2/3, .........,162`

Here,
Common ratio, r =`(2/9)/(2/27)` = 3

Last term, l = 162

∴ 3^rd term from an end =`1/r^2`

= `162/(3)^2`

= `162/9`

= 18