Question

Find the seventh term from the end of the series :

`sqrt(2), 2, 2sqrt(2), ........., 32.`

Answer 1

Given series: `sqrt(2), 2, 2sqrt(2), ........., 32.`

Now, `2/sqrt(2) = (2sqrt(2))/2 = sqrt(2)`

So, the given series is a G.P. with common ratio, r = `sqrt(2)`

Here, last term, l = 32

∴ 7^th term from an end = `1/r^6`

= `32/(sqrt(2))^6`

= `32/8`

= 4