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प्रश्न
Find, which of the following sequence from a G.P. :
`1/8, 1/24, 1/72, 1/216, ................`
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उत्तर
Given sequence: `1/8,1/24,1/72,1/216, ................`
Now,
`(1/24)/(1/8) = 1/3, (1/72)/(1/24) = 1/3, (1/216)/(1/72) = 1/3`
Since `(1/24)/(1/8) = (1/72)/(1/24) = (1/216)/(1/72) = .......... = 1/3,` the given sequence is a G.P. with common ratio `1/3`.
संबंधित प्रश्न
The product of 3rd and 8th terms of a G.P. is 243. If its 4th term is 3, find its 7th term.
Find the geometric progression with 4th term = 54 and 7th term = 1458.
The fourth term, the seventh term and the last term of a geometric progression are 10, 80 and 2560 respectively. Find its first term, common ratio and number of terms.
If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that `a/x + c/y = 2`
Find the sum of G.P. :
`(x + y)/(x - y) + 1 + (x - y)/(x + y) + ..........` upto n terms.
Find the geometric mean between 14 and `7/32`
Q 3.1
Q 7
The first term of a G.P. is –3 and the square of the second term is equal to its 4th term. Find its 7th term.
The first two terms of a G.P. are 125 and 25 respectively. Find the 5th and the 6th terms of the G.P.
