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Find the 8th term of a GP., if its common ratio is 2 and 10th term is 768.

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Question

Find the 8th term of a GP., if its common ratio is 2 and 10th term is 768.

Sum
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Solution

Given,

Common ratio (r) = 2

By formula,

⇒ an = arn − 1

Given,

10th term of G.P. = 768

⇒ a10 = 768

⇒ ar10 − 1 = 768

⇒ ar9 = 768

⇒ a × 29 = 768

⇒ a × 512 = 768

⇒ a = `768/512 = 3/2`

8th term of G.P. is given by:

⇒ a8 = ar8 − 1

⇒ a8 = ar7

⇒ a8 = `3/2 × 2^7`

⇒ a8 = 3 × 26

⇒ a8 = 3 × 64 = 192.

Hence, 8th term of a G.P. is given by 192.

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Chapter 11: Geometric Progression - TEST YOURSELF [Page 156]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 11 Geometric Progression
TEST YOURSELF | Q 8. | Page 156
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