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Chapters
1: Real Numbers
Algebra
2: Polynomials
3: Linear Equations in Two Variables
4: Quadratic Equations
5: Arithmetic Progression
Coordinate Geometry
6: Coordinate Geometry
Geometry
7: Triangles
8: Circles
9: Constructions
Trigonometry
▶ 10: Trignometric Ratios
11: T-Ratios of Some Particular Angles
12: Trigonometric Ratios of Some Complemantary Angles
13: Trigonometric identities
14: Heights and Distances
Mensuration
15: Perimeter And Area of Plane Figures
16: Area of Circle, Sector and Segment
17: Volumes and Surface Areas of Solids
Statistics and Probability
18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
19: Probability
Chapter 20: Additional Questions
![R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 10 - Trignometric Ratios R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 10 - Trignometric Ratios - Shaalaa.com](/images/mathematics-english-class-10_6:8f062ea57bdf49abb4f6d22550b39d56.jpg)
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Solutions for Chapter 10: Trignometric Ratios
Below listed, you can find solutions for Chapter 10 of CBSE, Karnataka Board R.S. Aggarwal for Mathematics [English] Class 10.
R.S. Aggarwal solutions for Mathematics [English] Class 10 10 Trignometric Ratios EXERCISE 10 [Pages 546 - 548]
If `sin θ = sqrt(3)/2`, find the value of all T-ratios of θ.
If `cos θ = 7/25`, find the values of all T-ratios of θ.
If `tan θ = 15/8`, find the values of all T-ratios of θ.
If cot θ = 2, find the values of all T-ratios of θ.
If cosec θ = `sqrt(10)`, find the values of all T-ratios of θ.
If `sin θ = (a^2 - b^2)/(a^2 + b^2)`, find the values of all T-ratios of θ.
If `sin θ = c/sqrt(c^2 + d^2)`, where d > 0 then find the values of cos θ and tan θ.
If `sqrt(3) tan θ =1` then evaluate (cos2θ – sin2θ).
If 4 tan θ = 3 then prove that sin θ cos θ = `12/25`.
If `sin θ = a/b` then prove that `(sec θ + tan θ) = sqrt((b + a)/(b - a)`.
If `tan θ = a/b` then prove that `((a sin theta - b cos theta)/(a sin theta + b cos theta)) = ((a^2 - b^2))/((a^2 + b^2))`.
If `sin θ = 12/13` then evaluate `((2 sin θ - 3 cos θ)/(4 sin θ - 9 cos θ))`.
If `tan θ = 1/2` then evaluate `((cos θ)/(sin θ) + (sin θ)/(1 + cos θ))`.
If `sin α = 1/2` then prove that (3 cos α – 4 cos3 α) = 0.
If 3 cot θ = 2 then prove that `((4 sin θ - 3 cos θ))/((2 sin θ + 6 cos θ)) = 1/3`.
If `sec θ = 17/8` then prove that `(3 - 4 sin^2θ)/(4 cos^2θ - 3) = (3 - tan^2 θ)/(1 - 3 tan^2θ)`.
If `tan θ = 20/21` then prove that `((1 - sin θ + cos θ))/((1 + sin θ + cos θ)) = 3/7`.
If `tan θ = 1/sqrt(7)` then prove that `(("cosec"^2θ + sec^2θ))/(("cosec"^2θ - sec^2θ)) = 4/3`.
If `sin θ = 3/4` prove that `sqrt(("cosec"^2θ - cot^2θ)/(sec^2θ - 1)) = sqrt(7)/3`.
If 3 tan A = 4 then prove that `sqrt((sec A - "cosec" A)/(sec A + "cosec" A)) = 1/sqrt(7)`.
If 3 tan A = 4 then prove that `sqrt((1 - sin A)/(1 + cos A)) = 1/(2sqrt(2)`.
If `cot θ = 15/8` then evaluate `((1 + sin θ)(1 - sin θ))/((1 + cos θ)(1 - cos θ))`.
In a ΔАBC, if ∠B = 90° and tan A = 1 then prove that 2 sin A cos A = 1.
In the given figure, ABCD is a rectangle in which diag. AC = 17 cm, ∠BCA = θ and `sin θ = 8/17`.
Find (i) the area of rect. ABCD,
(ii) the perimeter of rect. ABCD.

If x = cosec A + cos A and y = cosec A – cos A then prove that `(2/(x + y))^2 + ((x - y)/2)^2 = 1`.
If x = cot A + cos A and y = cot A – cos A then prove that `((x - y)/(x + y))^2 + ((x - y)/2)^2 = 1`.
In ΔABC, ∠A = 0, ∠B = 90° and ∠C = `phi`. If BC = x and AC = (x + 2), find the values of
- `(sqrt(x + 1)) cot phi`,
- `(sqrt(x^3 + x^2)) tan θ`,
- cos θ.

If `cot A + 1/(cot A) = 2`, find the value of `(cot^2A + 1/(cot^2A))`.
If `sqrt(3) tan θ = 3 sin θ`, find the value of sin θ.
If ∠A and ∠B are acute angles such that sin A = sin B then prove that ∠A = ∠B.
If ∠A and ∠B are acute angles such that tan A = tan B then prove that ∠A = ∠B.
If 1 + sin2θ = 3 sin θ cos θ, then prove that tan θ = 1 or `1/2`.
R.S. Aggarwal solutions for Mathematics [English] Class 10 10 Trignometric Ratios MULTIPLE-CHOICE QUESTIONS (MCQ) [Pages 555 - 556]
Choose the correct answer in each of the following questions:
If `tan θ = 8/15` then cosec θ = ?
`15/17`
`17/15`
`17/8`
`8/17`
If `tan θ = sqrt(3)` then sec θ = ?
2
`1/2`
`sqrt(3)/2`
`2/sqrt(3)`
If cosec θ = `sqrt(10)` then sec θ = ?
`1/sqrt(10)`
`2/sqrt(10)`
`3/sqrt(10)`
`sqrt(10)/3`
If `sec θ = 25/7` then sin θ = ?
`7/25`
`24/25`
`7/24`
`24/7`
If `sin θ = 1/2` then cot θ = ?
`sqrt(3)/2`
1
`sqrt(3)`
`1/sqrt(3)`
If `cos θ = 4/5` then tan θ = ?
`3/4`
`4/3`
`3/5`
`5/3`
If `tan θ = 4/3` then (sin θ + cos θ) = ?
`7/3`
`7/4`
`7/5`
`5/7`
If (tan θ + cot θ) = 5 then (tan2θ + cot2θ) = ?
27
25
24
23
If `(cos θ + sec θ) = 5/2` then (cos2θ + sec2θ) = ?
`17/4`
`21/4`
`29/4`
`33/4`
If 4 tan θ = 3 then (cos2θ – sin2θ) = ?
`4/25`
`7/25`
1
`11/25`
If 4 cot θ = 3 then `((sin θ - cos θ)/(sin θ + cos θ))` = ?
`3/7`
`2/7`
`1/7`
0
If 3 cos θ = 2 then (2 sec2θ + 2 tan2θ – 7) = ?
0
1
3
4
If sec θ + tan θ + 1 = 0 then (sec θ – tan θ) = ?
1
–1
0
2
If cos A + cos2 A = 1 then (sin2 A + sin4 A) = ?
`1/2`
2
1
4
If `sin θ = sqrt(3)/2` then (cosec θ + cot θ) = ?
`(2 + sqrt(3))`
`2sqrt(3)`
`sqrt(2)`
`sqrt(3)`
If `sqrt(3) tan θ = 3 sin θ` then (sin2θ – cos2θ) = ?
`1/3`
`1/sqrt(3)`
`sqrt(3)`
`2/sqrt(3)`
Solutions for 10: Trignometric Ratios
![R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 10 - Trignometric Ratios R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 10 - Trignometric Ratios - Shaalaa.com](/images/mathematics-english-class-10_6:8f062ea57bdf49abb4f6d22550b39d56.jpg)
R.S. Aggarwal solutions for Mathematics [English] Class 10 chapter 10 - Trignometric Ratios
Shaalaa.com has the CBSE, Karnataka Board Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board 10 (Trignometric Ratios) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Mathematics [English] Class 10 chapter 10 Trignometric Ratios are .
Using R.S. Aggarwal Mathematics [English] Class 10 solutions Trignometric Ratios exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in R.S. Aggarwal Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board Mathematics [English] Class 10 students prefer R.S. Aggarwal Textbook Solutions to score more in exams.
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