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Question
In a ΔАBC, if ∠B = 90° and tan A = 1 then prove that 2 sin A cos A = 1.
Theorem
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Solution

Given: tan A = 1
To prove: 2 sin A cos A = 1
Proof:
Given, а ΔАВC in which tan A = 1.
Then, tan A = 1 ⇒ `(BC)/(AB) = 1`.
Let BC = x. Then, AB = x.
∴ AC2 = (AB2 + BC2)
= (x2 + x2)
= 2x2
⇒ `AC = sqrt(2x^2)`
⇒ `AC = sqrt(2)x`.
∴ `2 sin A cos A = 2 xx ((BC)/(AC) xx (AB)/(AC))`
= `(2 xx x/(sqrt(2)x) xx x/(sqrt(2)x))`
= 1
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