English

In a ΔАBC, if ∠B = 90° and tan A = 1 then prove that 2 sin A cos A = 1.

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Question

In a ΔАBC, if ∠B = 90° and tan A = 1 then prove that 2 sin A cos A = 1.

Theorem
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Solution


Given: tan A = 1

To prove: 2 sin A cos A = 1

Proof:

Given, а ΔАВC in which tan A = 1.

Then, tan A = 1 ⇒ `(BC)/(AB) = 1`.

Let BC = x. Then, AB = x.

∴ AC2 = (AB2 + BC2)

= (x2 + x2)

= 2x2

⇒ `AC = sqrt(2x^2)`

⇒ `AC = sqrt(2)x`.

∴ `2 sin A cos A = 2 xx ((BC)/(AC) xx (AB)/(AC))`

= `(2 xx x/(sqrt(2)x) xx x/(sqrt(2)x))`

= 1

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Chapter 10: Trignometric Ratios - EXERCISE 10 [Page 547]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 10 Trignometric Ratios
EXERCISE 10 | Q 22. | Page 547
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