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Question
If 4 cot θ = 3 then `((sin θ - cos θ)/(sin θ + cos θ))` = ?
Options
`3/7`
`2/7`
`1/7`
0
MCQ
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Solution
`bb(1/7)`
Explanation:
`((sin θ - cos θ)/(sin θ + cos θ)) = ((1 - cot θ)/(1 + cot θ))` ...[Dividing num. and denom. by sin θ]
= `((1 - 3/4))/((1 + 3/4))` ...`[∵ cot θ = 3/4]`
= `((1/4))/((7/4))`
= `1/7`
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