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Chapter 2: Functions
Chapter 3: Binary Operations
Chapter 4: Inverse Trigonometric Functions
Chapter 5: Algebra of Matrices
Chapter 6: Determinants
Chapter 7: Adjoint and Inverse of a Matrix
Chapter 8: Solution of Simultaneous Linear Equations
Chapter 9: Continuity
Chapter 10: Differentiability
Chapter 11: Differentiation
Chapter 12: Higher Order Derivatives
Chapter 13: Derivative as a Rate Measurer
Chapter 14: Differentials, Errors and Approximations
Chapter 15: Mean Value Theorems
Chapter 16: Tangents and Normals
Chapter 17: Increasing and Decreasing Functions
Chapter 18: Maxima and Minima
Chapter 19: Indefinite Integrals
Chapter 20: Definite Integrals
Chapter 21: Areas of Bounded Regions
Chapter 22: Differential Equations
Chapter 23: Algebra of Vectors
Chapter 24: Scalar Or Dot Product
Chapter 25: Vector or Cross Product
Chapter 26: Scalar Triple Product
Chapter 27: Direction Cosines and Direction Ratios
Chapter 28: Straight Line in Space
Chapter 29: The Plane
Chapter 30: Linear programming
Chapter 31: Probability
Chapter 32: Mean and Variance of a Random Variable
Chapter 33: Binomial Distribution

Solutions for Chapter 20: Definite Integrals
Below listed, you can find solutions for Chapter 20 of CBSE, Karnataka Board PUC RD Sharma for Class 12 Maths.
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Exercise 20.1 [Pages 16 - 18]
\[\int\limits_{\pi/4}^{\pi/2} \cot x\ dx\]
Evaluate the following definite integrals:
\[\int\limits_0^1 \left( x e^x + \cos\frac{\pi x}{4} \right) dx\]
Evaluate the following definite integral:
\[\int\limits_0^k \frac{1}{2 + 8 x^2} dx = \frac{\pi}{16},\] find the value of k.
\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Exercise 20.2 [Pages 38 - 40]
\[\int\limits_0^{( \pi )^{2/3}} \sqrt{x} \cos^2 x^{3/2} dx\]
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Exercise 20.3 [Pages 55 - 56]
\[\int\limits_1^4 f\left( x \right) dx, where f\left( x \right) = \begin{cases}7x + 3 & , & \text{if }1 \leq x \leq 3 \\ 8x & , & \text{if }3 \leq x \leq 4\end{cases}\]
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
\[\int\limits_0^2 \left| x^2 - 3x + 2 \right| dx\]
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Exercise 20.4 [Page 61]
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
\[\int_a^b \frac{x^\frac{1}{n}}{x^\frac{1}{n} + \left( a + b - x \right)^\frac{1}{n}}dx, n \in N, n \geq 2\]
If \[f\left( a + b - x \right) = f\left( x \right)\] , then prove that \[\int_a^b xf\left( x \right)dx = \frac{a + b}{2} \int_a^b f\left( x \right)dx\]
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Exercise 20.5 [Pages 94 - 96]
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate
\[\int\limits_0^\pi \frac{x}{1 + \sin \alpha \sin x}dx\]
Evaluate the following integral:
Evaluate the following integral:
`int_0^(2a)f(x)dx`
Evaluate :
If `f` is an integrable function such that f(2a − x) = f(x), then prove that
If f(2a − x) = −f(x), prove that
If f is an integrable function, show that
\[\int\limits_{- a}^a f\left( x^2 \right) dx = 2 \int\limits_0^a f\left( x^2 \right) dx\]
If f is an integrable function, show that
If f (x) is a continuous function defined on [0, 2a]. Then, prove that
If \[f\left( a + b - x \right) = f\left( x \right)\] , then prove that
If f(x) is a continuous function defined on [−a, a], then prove that
Prove that:
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Exercise 20.6 [Pages 110 - 111]
Evaluate the following integrals as limit of sums:
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Very Short Answers [Pages 115 - 116]
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Solve each of the following integral:
If \[\int\limits_0^1 \left( 3 x^2 + 2x + k \right) dx = 0,\] find the value of k.
If \[\int\limits_0^a 3 x^2 dx = 8,\] write the value of a.
If \[f\left( x \right) = \int_0^x t\sin tdt\], the write the value of \[f'\left( x \right)\]
If \[\int_0^a \frac{1}{4 + x^2}dx = \frac{\pi}{8}\] , find the value of a.
Write the coefficient a, b, c of which the value of the integral
Evaluate :
\[\int\limits_0^1 \left\{ x \right\} dx,\] where {x} denotes the fractional part of x.
If \[\left[ \cdot \right] and \left\{ \cdot \right\}\] denote respectively the greatest integer and fractional part functions respectively, evaluate the following integrals:
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals MCQ [Pages 117 - 120]
π/2
π/4
π/6
π/8
\[\int\limits_0^\pi \frac{1}{1 + \sin x} dx\] equals
0
1/2
2
3/2
The value of \[\int\limits_0^\pi \frac{x \tan x}{\sec x + \cos x} dx\] is __________ .
- \[\frac{\pi^2}{4}\]
- \[\frac{\pi^2}{2}\]
- \[\frac{3 \pi^2}{2}\]
\[\frac{\pi^2}{3}\]
The value of \[\int\limits_0^{2\pi} \sqrt{1 + \sin\frac{x}{2}}dx\] is
0
2
8
4
The value of the integral \[\int\limits_0^{\pi/2} \frac{\sqrt{\cos x}}{\sqrt{\cos x} + \sqrt{\sin x}} dx\] is
0
π/2
π/4
none of these
\[\int\limits_0^\infty \frac{1}{1 + e^x} dx\] equals
log 2 − 1
log 2
log 4 − 1
− log 2
\[\int_0^\frac{\pi^2}{4} \frac{\sin\sqrt{x}}{\sqrt{x}} dx\] equals
2
1
π/4
π2/8
- \[\log\left( \frac{2}{3} \right)\]
- \[\log\left( \frac{3}{2} \right)\]
- \[\log\left( \frac{3}{4} \right)\]
- \[\log\left( \frac{4}{3} \right)\]
\[\int\limits_0^{\pi/2} \frac{1}{2 + \cos x} dx\] equals
- \[\frac{1}{3} \tan^{- 1} \left( \frac{1}{\sqrt{3}} \right)\]
- \[\frac{2}{\sqrt{3}} \tan^{- 1} \left( \frac{1}{\sqrt{3}} \right)\]
- \[\sqrt{3} \tan^{- 1} \left( \sqrt{3} \right)\]
- \[2\sqrt{3} \tan^{- 1} \sqrt{3}\]
`int_0^1 sqrt((1 - "x")/(1 + "x")) "dx"`
- \[\frac{\pi}{2}\]
\[\frac{\pi}{2} - 1\]
- \[\frac{\pi}{2} + 1\]
π + 1
None of these
\[\frac{\pi}{\sqrt{a^2 - b^2}}\]
- \[\frac{\pi}{ab}\]
\[\frac{\pi}{a^2 + b^2}\]
(a + b) π
π/3
π/6
π/12
π/2
Given that \[\int\limits_0^\infty \frac{x^2}{\left( x^2 + a^2 \right)\left( x^2 + b^2 \right)\left( x^2 + c^2 \right)} dx = \frac{\pi}{2\left( a + b \right)\left( b + c \right)\left( c + a \right)},\] the value of \[\int\limits_0^\infty \frac{dx}{\left( x^2 + 4 \right)\left( x^2 + 9 \right)},\]
- \[\frac{\pi}{60}\]
- \[\frac{\pi}{20}\]
- \[\frac{\pi}{40}\]
- \[\frac{\pi}{80}\]
1
e − 1
e + 1
0
- \[\frac{\pi}{12}\]
- \[\frac{\pi}{6}\]
- \[\frac{\pi}{4}\]
- \[\frac{\pi}{3}\]
- \[\frac{\pi}{12} + \log\left( 2\sqrt{2} \right)\]
- \[\frac{\pi}{2} + \log\left( 2\sqrt{2} \right)\]
- \[\frac{\pi}{6} + \log\left( 2\sqrt{2} \right)\]
\[\frac{\pi}{3} + \log\left( 2\sqrt{2} \right)\]
The value of the integral \[\int\limits_0^\infty \frac{x}{\left( 1 + x \right)\left( 1 + x^2 \right)} dx\]
- \[\frac{\pi}{2}\]
- \[\frac{\pi}{4}\]
- \[\frac{\pi}{6}\]
- \[\frac{\pi}{3}\]
1
2
− 1
− 2
- \[\frac{ \pi}{4}\]
- \[\frac{\pi}{3}\]
- \[\frac{\pi}{2}\]
π
The value of \[\int\limits_0^{\pi/2} \cos x\ e^{\sin x}\ dx\] is
1
e − 1
0
− 1
If \[\int\limits_0^a \frac{1}{1 + 4 x^2} dx = \frac{\pi}{8},\] then a equals
- \[\frac{\pi}{2}\]
- \[\frac{1}{2}\]
- \[\frac{\pi}{4}\]
1
If \[\int\limits_0^1 f\left( x \right) dx = 1, \int\limits_0^1 xf\left( x \right) dx = a, \int\limits_0^1 x^2 f\left( x \right) dx = a^2 , then \int\limits_0^1 \left( a - x \right)^2 f\left( x \right) dx\] equals
4a2
0
2a2
none of these
The value of \[\int\limits_{- \pi}^\pi \sin^3 x \cos^2 x\ dx\] is
- \[\frac{\pi^4}{2}\]
- \[\frac{\pi^4}{4}\]
0
none of these
loge 3
- \[\log_e \sqrt{3}\]
- \[\frac{1}{2}\log\left( - 1 \right)\]
log (−1)
−2
2
0
4
The derivative of \[f\left( x \right) = \int\limits_{x^2}^{x^3} \frac{1}{\log_e t} dt, \left( x > 0 \right),\] is
- \[\frac{1}{3 \ln x}\]
- \[\frac{1}{3 \ln x} - \frac{1}{2 \ln x}\]
(ln x)−1 x (x − 1)
- \[\frac{3 x^2}{\ln x}\]
If \[I_{10} = \int\limits_0^{\pi/2} x^{10} \sin x\ dx,\] then the value of I10 + 90I8 is
- \[9 \left( \frac{\pi}{2} \right)^9\]
- \[10 \left( \frac{\pi}{2} \right)^9\]
- \[\left( \frac{\pi}{2} \right)^9\]
- \[9 \left( \frac{\pi}{2} \right)^8\]
`15/16`
`3/16`
`-3/16`
`-16/3`
- \[\ln\left( \frac{1}{3} \right)\]
- \[\ln\left( \frac{2}{3} \right)\]
- \[\ln\left( \frac{3}{2} \right)\]
- \[\ln\left( \frac{4}{3} \right)\]
The value of the integral \[\int\limits_{- 2}^2 \left| 1 - x^2 \right| dx\] is ________ .
4
2
−2
0
0
1
π/2
π/4
0
π
π/2
π/4
π/4
π/2
π
1
π
π/2
0
2π
The value of \[\int\limits_0^\pi \frac{1}{5 + 3 \cos x} dx\] is
π/4
π/8
π/2
0
π ln 2
−π ln 2
0
\[- \frac{\pi}{2}\ln 2\]
\[\int\limits_0^{2a} f\left( x \right) dx\] is equal to
- \[2 \int\limits_0^a f\left( x \right) dx\]
0
\[\int\limits_0^a f\left( x \right) dx + \int\limits_0^a f\left( 2a - x \right) dx\]
- \[\int\limits_0^a f\left( x \right) dx + \int\limits_0^{2a} f\left( 2a - x \right) dx\]
If f (a + b − x) = f (x), then \[\int\limits_a^b\] x f (x) dx is equal to
- \[\frac{a + b}{2} \int\limits_a^b f\left( b - x \right) dx\]
- \[\frac{a + b}{2} \int\limits_a^b f\left( b + x \right) dx\]
- \[\frac{b - a}{2} \int\limits_a^b f\left( x \right) dx\]
- \[\frac{b + a}{2} \int\limits_a^b f\left( x \right) dx\]
The value of \[\int\limits_0^1 \tan^{- 1} \left( \frac{2x - 1}{1 + x - x^2} \right) dx,\] is
1
0
−1
π/4
The value of \[\int\limits_0^{\pi/2} \log\left( \frac{4 + 3 \sin x}{4 + 3 \cos x} \right) dx\] is
2
- \[\frac{3}{4}\]
0
−2
The value of \[\int\limits_{- \pi/2}^{\pi/2} \left( x^3 + x \cos x + \tan^5 x + 1 \right) dx, \] is
0
2
π
1
RD Sharma solutions for Class 12 Maths Chapter 20 Definite Integrals Revision Exercise [Pages 121 - 123]
\[\int\limits_0^4 x\sqrt{4 - x} dx\]
\[\int\limits_1^2 x\sqrt{3x - 2} dx\]
\[\int\limits_1^5 \frac{x}{\sqrt{2x - 1}} dx\]
\[\int\limits_0^1 \cos^{- 1} x dx\]
\[\int\limits_0^1 \tan^{- 1} x dx\]
\[\int\limits_0^1 \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) dx\]
\[\int\limits_0^1 \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) dx\]
\[\int\limits_0^{1/\sqrt{3}} \tan^{- 1} \left( \frac{3x - x^3}{1 - 3 x^2} \right) dx\]
\[\int\limits_0^1 \frac{1 - x}{1 + x} dx\]
\[\int\limits_0^{\pi/3} \frac{\cos x}{3 + 4 \sin x} dx\]
\[\int\limits_0^{\pi/2} \frac{\sin^2 x}{\left( 1 + \cos x \right)^2} dx\]
\[\int\limits_0^{\pi/2} \frac{\sin x}{\sqrt{1 + \cos x}} dx\]
\[\int\limits_0^{\pi/2} \frac{\cos x}{1 + \sin^2 x} dx\]
\[\int\limits_0^\pi \sin^3 x\left( 1 + 2 \cos x \right) \left( 1 + \cos x \right)^2 dx\]
\[\int\limits_0^\infty \frac{x}{\left( 1 + x \right)\left( 1 + x^2 \right)} dx\]
\[\int\limits_0^{\pi/4} \sin 2x \sin 3x dx\]
\[\int\limits_0^1 \sqrt{\frac{1 - x}{1 + x}} dx\]
\[\int\limits_1^2 \frac{1}{x^2} e^{- 1/x} dx\]
\[\int\limits_0^{\pi/4} \cos^4 x \sin^3 x dx\]
\[\int\limits_{\pi/3}^{\pi/2} \frac{\sqrt{1 + \cos x}}{\left( 1 - \cos x \right)^{5/2}} dx\]
\[\int\limits_0^{\pi/2} x^2 \cos 2x dx\]
\[\int\limits_0^1 \log\left( 1 + x \right) dx\]
Evaluate the following integrals :-
\[\int_2^4 \frac{x^2 + x}{\sqrt{2x + 1}}dx\]
\[\int\limits_0^1 x \left( \tan^{- 1} x \right)^2 dx\]
\[\int\limits_0^1 \left( \cos^{- 1} x \right)^2 dx\]
\[\int\limits_1^2 \frac{x + 3}{x\left( x + 2 \right)} dx\]
\[\int\limits_0^{\pi/4} e^x \sin x dx\]
\[\int\limits_0^{\pi/4} \tan^4 x dx\]
\[\int\limits_0^1 \left| 2x - 1 \right| dx\]
\[\int\limits_1^3 \left| x^2 - 2x \right| dx\]
\[\int\limits_0^{\pi/2} \left| \sin x - \cos x \right| dx\]
\[\int\limits_0^1 \left| \sin 2\pi x \right| dx\]
\[\int\limits_1^3 \left| x^2 - 4 \right| dx\]
\[\int\limits_{- \pi/2}^{\pi/2} \sin^9 x dx\]
\[\int\limits_{- 1/2}^{1/2} \cos x \log\left( \frac{1 + x}{1 - x} \right) dx\]
\[\int\limits_{- a}^a \frac{x e^{x^2}}{1 + x^2} dx\]
\[\int\limits_0^{\pi/2} \frac{1}{1 + \cot^7 x} dx\]
\[\int\limits_0^{2\pi} \cos^7 x dx\]
\[\int\limits_0^a \frac{\sqrt{x}}{\sqrt{x} + \sqrt{a - x}} dx\]
\[\int\limits_0^{\pi/2} \frac{1}{1 + \tan^3 x} dx\]
\[\int\limits_0^\pi \frac{x \sin x}{1 + \cos^2 x} dx\]
\[\int\limits_0^\pi x \sin x \cos^4 x dx\]
\[\int\limits_0^\pi \frac{x}{a^2 \cos^2 x + b^2 \sin^2 x} dx\]
\[\int\limits_{- \pi/4}^{\pi/4} \left| \tan x \right| dx\]
\[\int\limits_0^{15} \left[ x^2 \right] dx\]
\[\int\limits_0^\pi \frac{x}{1 + \cos \alpha \sin x} dx\]
\[\int\limits_0^{\pi/2} \frac{x \sin x \cos x}{\sin^4 x + \cos^4 x} dx\]
\[\int\limits_0^{\pi/2} \frac{\cos^2 x}{\sin x + \cos x} dx\]
\[\int\limits_0^\pi \cos 2x \log \sin x dx\]
\[\int\limits_0^\pi \frac{x}{a^2 - \cos^2 x} dx, a > 1\]
\[\int\limits_0^\pi \frac{x \tan x}{\sec x + \tan x} dx\]
\[\int\limits_2^3 \frac{\sqrt{x}}{\sqrt{5 - x} + \sqrt{x}} dx\]
\[\int\limits_0^{\pi/2} \frac{\sin^2 x}{\sin x + \cos x} dx\]
\[\int\limits_0^{\pi/2} \frac{x}{\sin^2 x + \cos^2 x} dx\]
\[\int\limits_{- \pi}^\pi x^{10} \sin^7 x dx\]
\[\int\limits_0^1 \cot^{- 1} \left( 1 - x + x^2 \right) dx\]
\[\int\limits_0^\pi \frac{dx}{6 - \cos x}dx\]
\[\int\limits_0^{\pi/2} \frac{1}{2 \cos x + 4 \sin x} dx\]
\[\int\limits_{\pi/6}^{\pi/2} \frac{\ cosec x \cot x}{1 + {cosec}^2 x} dx\]
\[\int\limits_0^{\pi/2} \frac{dx}{4 \cos x + 2 \sin x}dx\]
\[\int\limits_0^4 x dx\]
\[\int\limits_0^2 \left( 2 x^2 + 3 \right) dx\]
\[\int\limits_1^4 \left( x^2 + x \right) dx\]
\[\int\limits_{- 1}^1 e^{2x} dx\]
\[\int\limits_2^3 e^{- x} dx\]
\[\int\limits_1^3 \left( 2 x^2 + 5x \right) dx\]
\[\int\limits_1^3 \left( x^2 + 3x \right) dx\]
\[\int\limits_0^2 \left( x^2 + 2 \right) dx\]
\[\int\limits_0^3 \left( x^2 + 1 \right) dx\]
Solutions for Chapter 20: Definite Integrals

RD Sharma solutions for Class 12 Maths chapter 20 - Definite Integrals
Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Class 12 Maths CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Class 12 Maths CBSE, Karnataka Board PUC 20 (Definite Integrals) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Class 12 Maths chapter 20 Definite Integrals are Definite Integrals Problems, Indefinite Integral Problems, Comparison Between Differentiation and Integration, Integrals of Some Particular Functions, Indefinite Integral by Inspection, Some Properties of Indefinite Integral, Integration Using Trigonometric Identities, Introduction of Integrals, Evaluation of Definite Integrals by Substitution, Properties of Definite Integrals, Fundamental Theorem of Calculus, Definite Integral as the Limit of a Sum, Evaluation of Simple Integrals of the Following Types and Problems, Methods of Integration: Integration by Parts, Methods of Integration: Integration Using Partial Fractions, Methods of Integration: Integration by Substitution, Integration as an Inverse Process of Differentiation, Geometrical Interpretation of Indefinite Integrals.
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