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Question

\[\int\limits_0^1 \frac{1}{x^2 + 1} dx\]

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Solution

\[\int_0^1 \frac{1}{1 + x^2} d x\]

\[ = \left[ \tan^{- 1} x \right]_0^1 \]

\[ = \frac{\pi}{4} - 0\]

\[ = \frac{\pi}{4}\]

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Definite Integrals

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Chapter 19: Definite Integrals - Very Short Answers [Page 115]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12

Chapter 19 Definite Integrals
Very Short Answers | Q 8 | Page 115

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