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1 ∫ 0 1 X 2 + 1 D X

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प्रश्न

\[\int\limits_0^1 \frac{1}{x^2 + 1} dx\]
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उत्तर

\[\int_0^1 \frac{1}{1 + x^2} d x\]

\[ = \left[ \tan^{- 1} x \right]_0^1 \]

\[ = \frac{\pi}{4} - 0\]

\[ = \frac{\pi}{4}\]

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अध्याय 19: Definite Integrals - Very Short Answers [पृष्ठ ११५]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Very Short Answers | Q 8 | पृष्ठ ११५

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