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A ∫ − a X E X 2 1 + X 2 D X

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प्रश्न

\[\int\limits_{- a}^a \frac{x e^{x^2}}{1 + x^2} dx\]

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उत्तर

\[\int_{- a}^a \frac{x e^{x^2}}{1 + x^2} d x\]

\[\text{Let }f(x) = \frac{x e^{x^2}}{1 + x^2}\]

\[\text{Consider }f(-x) = - \frac{x e^{x^2}}{1 + x^2} = - f\left( x \right)\]

Thus f(x) is an odd function

Therefore,

\[ \int_{- a}^a \frac{x e^{x^2}}{1 + x^2} d x = 0\]

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अध्याय 19: Definite Integrals - Revision Exercise [पृष्ठ १२२]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Revision Exercise | Q 36 | पृष्ठ १२२

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