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Question

\[\int\limits_{- a}^a \frac{x e^{x^2}}{1 + x^2} dx\]

Sum
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Solution

\[\int_{- a}^a \frac{x e^{x^2}}{1 + x^2} d x\]

\[\text{Let }f(x) = \frac{x e^{x^2}}{1 + x^2}\]

\[\text{Consider }f(-x) = - \frac{x e^{x^2}}{1 + x^2} = - f\left( x \right)\]

Thus f(x) is an odd function

Therefore,

\[ \int_{- a}^a \frac{x e^{x^2}}{1 + x^2} d x = 0\]

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Definite Integrals
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Chapter 20: Definite Integrals - Revision Exercise [Page 122]

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RD Sharma Mathematics [English] Class 12
Chapter 20 Definite Integrals
Revision Exercise | Q 36 | Page 122

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