Advertisements
Advertisements
Question
Choose the correct alternative:
If f(x) is a continuous function and a < c < b, then `int_"a"^"c" f(x) "d"x + int_"c"^"b" f(x) "d"x` is
Options
`int_"a"^"b" f(x) "d"x - int_"a"^"c" f(x) "d"x`
`int_"a"^"c" f(x) "d"x - int_"a"^"b" f(x) "d"x`
`int_"a"^"b" f(x) "d"x`
0
MCQ
Advertisements
Solution
`int_"a"^"b" f(x) "d"x`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
\[\int\limits_0^{\pi/2} x^2 \cos\ 2x\ dx\]
\[\int_0^\frac{1}{2} \frac{x \sin^{- 1} x}{\sqrt{1 - x^2}}dx\]
\[\int_0^\frac{\pi}{2} \sqrt{\cos x - \cos^3 x}\left( \sec^2 x - 1 \right) \cos^2 xdx\]
\[\int_0^\pi \cos x\left| \cos x \right|dx\]
\[\int\limits_0^\pi \frac{x \tan x}{\sec x \ cosec x} dx\]
\[\int\limits_0^{\pi/2} \cos^2 x\ dx .\]
Solve each of the following integral:
\[\int_2^4 \frac{x}{x^2 + 1}dx\]
\[\int\limits_0^1 \left| 2x - 1 \right| dx\]
\[\int\limits_{- 1}^1 e^{2x} dx\]
Choose the correct alternative:
If n > 0, then Γ(n) is
