Advertisements
Advertisements
Question
Choose the correct alternative:
`int_0^1 (2x + 1) "d"x` is
Options
1
2
3
4
MCQ
Advertisements
Solution
2
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
\[\int\limits_0^\infty \frac{1}{a^2 + b^2 x^2} dx\]
\[\int\limits_0^1 x \left( 1 - x \right)^5 dx\]
\[\int\limits_0^{\pi/2} \frac{\cos x}{1 + \sin^2 x} dx\]
\[\int\limits_1^2 \frac{1}{x \left( 1 + \log x \right)^2} dx\]
\[\int\limits_0^2 \left( x + 3 \right) dx\]
\[\int\limits_0^\infty e^{- x} dx .\]
\[\int\limits_0^1 \frac{2x}{1 + x^2} dx\]
\[\int\limits_1^3 \left| x^2 - 2x \right| dx\]
Evaluate the following integrals as the limit of the sum:
`int_0^1 x^2 "d"x`
Evaluate `int (x^2 + x)/(x^4 - 9) "d"x`
