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प्रश्न
Choose the correct alternative:
`int_0^1 (2x + 1) "d"x` is
पर्याय
1
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4
MCQ
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उत्तर
2
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
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संबंधित प्रश्न
\[\int\limits_{\pi/4}^{\pi/2} \cot x\ dx\]
\[\int\limits_{- \pi/4}^{\pi/4} \frac{1}{1 + \sin x} dx\]
\[\int\limits_a^b \cos\ x\ dx\]
\[\int\limits_0^2 \left( x^2 + 2x + 1 \right) dx\]
\[\int\limits_a^b \frac{f\left( x \right)}{f\left( x \right) + f\left( a + b - x \right)} dx .\]
\[\int\limits_0^{\pi/2} \frac{\cos x}{\left( 2 + \sin x \right)\left( 1 + \sin x \right)} dx\] equals
\[\int\limits_{- \pi/2}^{\pi/2} \sin\left| x \right| dx\] is equal to
\[\int\limits_0^{\pi/2} \frac{1}{1 + \tan x} dx\] is equal to
\[\int\limits_0^{\pi/2} \frac{\sin x}{\sin x + \cos x} dx\] equals to
\[\int\limits_0^{\pi/2} \frac{\sin^2 x}{\sin x + \cos x} dx\]
