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प्रश्न
Choose the correct alternative:
`int_0^1 (2x + 1) "d"x` is
पर्याय
1
2
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4
MCQ
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उत्तर
2
shaalaa.com
Definite Integrals
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
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संबंधित प्रश्न
\[\int\limits_0^1 \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) dx\]
\[\int\limits_0^{\pi/4} \left( \sqrt{\tan}x + \sqrt{\cot}x \right) dx\]
\[\int\limits_0^{\pi/6} \cos^{- 3} 2 \theta \sin 2\ \theta\ d\ \theta\]
\[\int_{- \frac{\pi}{4}}^\frac{\pi}{2} \sin x\left| \sin x \right|dx\]
\[\int\limits_0^1 \log\left( \frac{1}{x} - 1 \right) dx\]
\[\int\limits_0^1 \left( 3 x^2 + 5x \right) dx\]
\[\int\limits_0^3 \frac{1}{x^2 + 9} dx .\]
\[\int\limits_0^\pi \frac{1}{1 + \sin x} dx\] equals
Using second fundamental theorem, evaluate the following:
`int_0^1 x"e"^(x^2) "d"x`
Evaluate the following using properties of definite integral:
`int_0^1 x/((1 - x)^(3/4)) "d"x`
