Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int_0^1 (2x + 1) "d"x` is
विकल्प
1
2
3
4
MCQ
Advertisements
उत्तर
2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_1^2 e^{2x} \left( \frac{1}{x} - \frac{1}{2 x^2} \right) dx\]
\[\int_{- 2}^2 x e^\left| x \right| dx\]
\[\int\limits_{- \pi/2}^{\pi/2} \log\left( \frac{2 - \sin x}{2 + \sin x} \right) dx\]
Evaluate :
\[\int\limits_2^3 3^x dx .\]
\[\int_0^\frac{\pi^2}{4} \frac{\sin\sqrt{x}}{\sqrt{x}} dx\] equals
If \[\int\limits_0^a \frac{1}{1 + 4 x^2} dx = \frac{\pi}{8},\] then a equals
\[\int\limits_0^\pi \frac{x}{a^2 \cos^2 x + b^2 \sin^2 x} dx\]
\[\int\limits_1^3 \left( x^2 + 3x \right) dx\]
`int "e"^x ((1 - x)/(1 + x^2))^2 "d"x` is equal to ______.
Given `int "e"^"x" (("x" - 1)/("x"^2)) "dx" = "e"^"x" "f"("x") + "c"`. Then f(x) satisfying the equation is:
