Advertisements
Advertisements
Question
Choose the correct alternative:
The value of `int_(- pi/2)^(pi/2) cos x "d"x` is
Options
0
2
1
4
MCQ
Advertisements
Solution
2
shaalaa.com
Definite Integrals
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
\[\int\limits_0^{\pi/2} \left( a^2 \cos^2 x + b^2 \sin^2 x \right) dx\]
\[\int\limits_0^1 \frac{1}{2 x^2 + x + 1} dx\]
\[\int\limits_{- 1}^1 5 x^4 \sqrt{x^5 + 1} dx\]
\[\int_0^\frac{\pi}{2} \frac{\cos^2 x}{1 + 3 \sin^2 x}dx\]
\[\int\limits_0^1 \left( \cos^{- 1} x \right)^2 dx\]
\[\int\limits_0^2 \left( 3 x^2 - 2 \right) dx\]
\[\int\limits_0^{\pi/2} \sin\ 2x\ \log\ \tan x\ dx\] is equal to
\[\int\limits_0^1 \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) dx\]
Evaluate the following:
`int_(-1)^1 "f"(x) "d"x` where f(x) = `{{:(x",", x ≥ 0),(-x",", x < 0):}`
Choose the correct alternative:
Γ(1) is
