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प्रश्न
Choose the correct alternative:
The value of `int_(- pi/2)^(pi/2) cos x "d"x` is
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0
2
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4
MCQ
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उत्तर
2
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संबंधित प्रश्न
\[\int\limits_0^{\pi/2} x \cos\ x\ dx\]
\[\int\limits_1^e \frac{\log x}{x} dx\]
\[\int\limits_0^1 x e^{x^2} dx\]
\[\int\limits_0^{\pi/2} \frac{x + \sin x}{1 + \cos x} dx\]
\[\int_0^\frac{\pi}{2} \sqrt{\cos x - \cos^3 x}\left( \sec^2 x - 1 \right) \cos^2 xdx\]
\[\int\limits_{- \pi/4}^{\pi/4} \sin^2 x\ dx\]
\[\int\limits_2^3 \frac{1}{x}dx\]
The value of \[\int\limits_0^{2\pi} \sqrt{1 + \sin\frac{x}{2}}dx\] is
\[\int\limits_1^3 \left( 2 x^2 + 5x \right) dx\]
Using second fundamental theorem, evaluate the following:
`int_0^(1/4) sqrt(1 - 4) "d"x`
