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प्रश्न
Choose the correct alternative:
The value of `int_(- pi/2)^(pi/2) cos x "d"x` is
विकल्प
0
2
1
4
MCQ
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उत्तर
2
shaalaa.com
Definite Integrals
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संबंधित प्रश्न
\[\int\limits_0^{\pi/2} \cos^2 x\ dx\]
\[\int\limits_0^{\pi/6} \cos x \cos 2x\ dx\]
\[\int\limits_0^{\pi/2} \cos^4\ x\ dx\]
\[\int\limits_0^\pi x \sin x \cos^4 x\ dx\]
If \[f\left( x \right) = \int_0^x t\sin tdt\], the write the value of \[f'\left( x \right)\]
The value of \[\int\limits_0^{2\pi} \sqrt{1 + \sin\frac{x}{2}}dx\] is
\[\int\limits_0^4 x\sqrt{4 - x} dx\]
\[\int\limits_0^\pi x \sin x \cos^4 x dx\]
Using second fundamental theorem, evaluate the following:
`int_0^(pi/2) sqrt(1 + cos x) "d"x`
Evaluate `int (x^2"d"x)/(x^4 + x^2 - 2)`
