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प्रश्न
Choose the correct alternative:
The value of `int_(- pi/2)^(pi/2) cos x "d"x` is
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MCQ
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उत्तर
2
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संबंधित प्रश्न
\[\int\limits_0^{\pi/2} \sqrt{1 + \sin x}\ dx\]
\[\int\limits_0^2 \frac{1}{\sqrt{3 + 2x - x^2}} dx\]
\[\int\limits_0^{2\pi} e^{x/2} \sin\left( \frac{x}{2} + \frac{\pi}{4} \right) dx\]
\[\int\limits_1^4 \left( x^2 - x \right) dx\]
\[\int\limits_0^1 \left( 3 x^2 + 5x \right) dx\]
\[\int\limits_a^b e^x dx\]
\[\int\limits_0^{\pi/3} \frac{\cos x}{3 + 4 \sin x} dx\]
\[\int\limits_{\pi/6}^{\pi/2} \frac{\ cosec x \cot x}{1 + {cosec}^2 x} dx\]
\[\int\limits_0^2 \left( 2 x^2 + 3 \right) dx\]
Evaluate the following integrals as the limit of the sum:
`int_0^1 x^2 "d"x`
