Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
The value of `int_(- pi/2)^(pi/2) cos x "d"x` is
विकल्प
0
2
1
4
MCQ
Advertisements
उत्तर
2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_0^\pi \frac{1}{1 + \sin x} dx\]
\[\int\limits_0^{\pi/2} \frac{\sin \theta}{\sqrt{1 + \cos \theta}} d\theta\]
\[\int\limits_0^{\pi/2} x^2 \sin\ x\ dx\]
\[\int\limits_0^2 \left( x^2 + 2x + 1 \right) dx\]
\[\int\limits_0^{\pi/2} \sin^2 x\ dx .\]
\[\int\limits_0^{\pi/2} \frac{\sin^n x}{\sin^n x + \cos^n x} dx, n \in N .\]
\[\int\limits_0^{\pi/2} \sin\ 2x\ \log\ \tan x\ dx\] is equal to
Evaluate : \[\int e^{2x} \cdot \sin \left( 3x + 1 \right) dx\] .
\[\int\limits_{- 1}^1 e^{2x} dx\]
Evaluate: `int_(-1)^2 |x^3 - 3x^2 + 2x|dx`
