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प्रश्न
Choose the correct alternative:
The value of `int_(- pi/2)^(pi/2) cos x "d"x` is
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4
MCQ
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उत्तर
2
shaalaa.com
Definite Integrals
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संबंधित प्रश्न
\[\int\limits_0^{\pi/2} x \cos\ x\ dx\]
\[\int\limits_0^{\pi/2} \frac{1}{5 + 4 \sin x} dx\]
\[\int_0^\frac{1}{2} \frac{x \sin^{- 1} x}{\sqrt{1 - x^2}}dx\]
\[\int\limits_0^\pi \frac{x \tan x}{\sec x \ cosec x} dx\]
\[\int\limits_1^3 \left( 2x + 3 \right) dx\]
\[\int\limits_{- \pi/2}^{\pi/2} \sin^3 x\ dx .\]
\[\int\limits_0^3 \frac{1}{x^2 + 9} dx .\]
\[\int\limits_0^2 \sqrt{4 - x^2} dx\]
\[\int\limits_0^\pi x \sin x \cos^4 x dx\]
Evaluate the following:
`int ((x^2 + 2))/(x + 1) "d"x`
