Advertisements
Advertisements
प्रश्न
\[\int\limits_0^{\pi/2} \frac{1}{1 + \cot^7 x} dx\]
Advertisements
उत्तर
\[Let, I = \int_0^\frac{\pi}{2} \frac{1}{1 + co t^7 x} d x ..............(1)\]
\[ = \int_0^\frac{\pi}{2} \frac{1}{1 + co t^7 \left( \frac{\pi}{2} - x \right)} d x\]
\[ = \int_0^\frac{\pi}{2} \frac{1}{1 + \tan^7 x} d x ..............(2)\]
Adding (1) and (2)
\[2I = \int_0^\frac{\pi}{2} \frac{1}{1 + co t^7 x} + \frac{1}{1 + \tan^7 x} d x \]
\[ = \int_0^\frac{\pi}{2} \frac{2 + co t^7 x + \tan^7 x}{\left( 1 + co t^7 x \right)\left( 1 + \tan^7 x \right)}dx\]
\[ = \int_0^\frac{\pi}{2} \frac{2 + co t^7 x + \tan^7 x}{2 + co t^7 x + \tan^7 x}dx\]
\[ = \int_0^\frac{\pi}{2} dx\]
\[ = \left[ x \right]_0^\frac{\pi}{2} \]
\[ = \frac{\pi}{2}\]
\[Hence, I = \frac{\pi}{4}\]
APPEARS IN
संबंधित प्रश्न
Evaluate the following integral:
Evaluate each of the following integral:
If \[\int\limits_0^a 3 x^2 dx = 8,\] write the value of a.
If \[f\left( x \right) = \int_0^x t\sin tdt\], the write the value of \[f'\left( x \right)\]
If \[\int\limits_0^a \frac{1}{1 + 4 x^2} dx = \frac{\pi}{8},\] then a equals
The value of \[\int\limits_0^1 \tan^{- 1} \left( \frac{2x - 1}{1 + x - x^2} \right) dx,\] is
\[\int\limits_0^4 x\sqrt{4 - x} dx\]
\[\int\limits_1^2 \frac{x + 3}{x\left( x + 2 \right)} dx\]
\[\int\limits_0^{\pi/4} \tan^4 x dx\]
\[\int\limits_0^1 \cot^{- 1} \left( 1 - x + x^2 \right) dx\]
\[\int\limits_0^3 \left( x^2 + 1 \right) dx\]
Prove that `int_a^b ƒ ("x") d"x" = int_a^bƒ(a + b - "x") d"x" and "hence evaluate" int_(π/6)^(π/3) (d"x")/(1+sqrt(tan "x")`
Using second fundamental theorem, evaluate the following:
`int_0^1 "e"^(2x) "d"x`
Evaluate the following using properties of definite integral:
`int_(- pi/2)^(pi/2) sin^2theta "d"theta`
Choose the correct alternative:
Γ(1) is
Choose the correct alternative:
`Γ(3/2)`
