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Π / 2 ∫ 0 Sin θ √ 1 + Cos θ D θ

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प्रश्न

\[\int\limits_0^{\pi/2} \frac{\sin \theta}{\sqrt{1 + \cos \theta}} d\theta\]
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उत्तर

\[Let\ I = \int_0^\frac{\pi}{2} \frac{\sin \theta}{\sqrt{1 + \cos \theta}} d \theta . \]

\[Let\ \cos\ \theta = t . Then, - \sin\ \theta\ d\theta\ = dt\]

\[When\ \theta = 0, t = 1\ and\ \theta = \frac{\pi}{2}, t = 0\]

\[ \therefore I = \int_0^\frac{\pi}{2} \frac{\sin \theta}{\sqrt{1 + \cos \theta}} d \theta\]

\[ = \int_1^0 \frac{- dt}{\sqrt{1 + t}}\]

\[ = \int_0^1 \frac{dt}{\sqrt{1 + t}}\]

\[ = 2 \left[ \sqrt{1 + t} \right]_0^1 \]

\[ = 2\left( \sqrt{2} - 1 \right)\]

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अध्याय 19: Definite Integrals - Exercise 20.2 [पृष्ठ ३९]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Exercise 20.2 | Q 13 | पृष्ठ ३९

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