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प्रश्न

\[\int\limits_0^{\pi/2} \frac{\cos x}{1 + \sin^2 x} dx\]

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उत्तर

\[\int_0^\frac{\pi}{2} \frac{\cos x}{1 + \sin^2 x} d x\]

\[Let \sin x = t,\text{ then }\cos x dx = dt\]

\[\text{When }x \to 0 ; t \to 0\]

\[\text{And }x \to \frac{\pi}{2}; t \to 1\]

Therefore the integral becomes

\[ \int_0^1 \frac{dt}{1 + t^2}\]

\[ = \left[ \tan^{- 1} x \right]_0^1 \]

\[ = \frac{\pi}{4}\]

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अध्याय 19: Definite Integrals - Revision Exercise [पृष्ठ १२१]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Revision Exercise | Q 13 | पृष्ठ १२१

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