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Π / 4 ∫ 0 Tan 2 X D X .

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Question

\[\int\limits_0^{\pi/4} \tan^2 x\ dx .\]
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Solution

\[\int_0^\frac{\pi}{4} \tan^2 x\ d x\]

\[ = \int_0^\frac{\pi}{4} \left( se c^2 x - 1 \right) d x\]

\[ = \left[ \tan x - x \right]_0^\frac{\pi}{4} \]

\[ = 1 - \frac{\pi}{4} - 0\]

\[ = 1 - \frac{\pi}{4}\]

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Chapter 19: Definite Integrals - Very Short Answers [Page 115]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 19 Definite Integrals
Very Short Answers | Q 7 | Page 115

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