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Question
Evaluate the following:
`int_0^oo "e"^(-4x) x^4 "d"x`
Sum
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Solution
`int_0^oo "e"^(-4x) x^4 "d"x = int_0^oo x^"n" "e"^(-ax) "d"x`
`("n"!)/("a"^("n" + 1))`
Where n = 4
a = 4
So the integral becomes `(4!)/4^5 = (4 xx 3 xx 2)/(4 xx 4 xx 4 xx 4 xx 4)`
= `3/128`
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Chapter 2: Integral Calculus – 1 - Exercise 2.10 [Page 51]
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