Advertisements
Advertisements
Question
Choose the correct alternative:
`int_0^oo "e"^(-2x) "d"x` is
Options
0
1
2
`1/2`
MCQ
Advertisements
Solution
`1/2`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
\[\int\limits_0^{\pi/4} \sec x dx\]
\[\int\limits_{\pi/6}^{\pi/4} cosec\ x\ dx\]
\[\int_0^\pi e^{2x} \cdot \sin\left( \frac{\pi}{4} + x \right) dx\]
\[\int\limits_0^{\pi/2} 2 \sin x \cos x \tan^{- 1} \left( \sin x \right) dx\]
\[\int\limits_{\pi/3}^{\pi/2} \frac{\sqrt{1 + \cos x}}{\left( 1 - \cos x \right)^{3/2}} dx\]
\[\int\limits_1^3 \left( 2x + 3 \right) dx\]
\[\int\limits_0^4 \left( x + e^{2x} \right) dx\]
\[\int\limits_0^\infty e^{- x} dx .\]
\[\int\limits_0^1 2^{x - \left[ x \right]} dx\]
Using second fundamental theorem, evaluate the following:
`int_0^(1/4) sqrt(1 - 4) "d"x`
