Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int_0^oo "e"^(-2x) "d"x` is
पर्याय
0
1
2
`1/2`
MCQ
Advertisements
उत्तर
`1/2`
shaalaa.com
Definite Integrals
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_0^{\pi/2} x \cos\ x\ dx\]
\[\int\limits_0^{\pi/2} x^2 \cos^2 x\ dx\]
\[\int\limits_4^{12} x \left( x - 4 \right)^{1/3} dx\]
\[\int\limits_0^1 \frac{1 - x^2}{\left( 1 + x^2 \right)^2} dx\]
\[\int\limits_0^{\pi/2} 2 \sin x \cos x \tan^{- 1} \left( \sin x \right) dx\]
\[\int\limits_3^5 \left( 2 - x \right) dx\]
\[\int\limits_2^3 x^2 dx\]
The value of \[\int\limits_0^\pi \frac{x \tan x}{\sec x + \cos x} dx\] is __________ .
\[\int\limits_0^\pi \frac{dx}{6 - \cos x}dx\]
Using second fundamental theorem, evaluate the following:
`int_0^(pi/2) sqrt(1 + cos x) "d"x`
