Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int_(-1)^1 x^3 "e"^(x^4) "d"x` is
पर्याय
1
`2 int_0^1 x^3 "e"^(x^4) "d"x`
0
`"e"^(x^4)`
MCQ
Advertisements
उत्तर
0
shaalaa.com
Definite Integrals
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_0^1 \frac{x}{x + 1} dx\]
\[\int\limits_0^{\pi/4} x^2 \sin\ x\ dx\]
\[\int\limits_0^1 \sqrt{x \left( 1 - x \right)} dx\]
\[\int\limits_0^{\pi/2} \frac{\sin^n x}{\sin^n x + \cos^n x} dx\]
\[\int\limits_0^a \frac{1}{x + \sqrt{a^2 - x^2}} dx\]
\[\int\limits_0^{\pi/2} \frac{x \sin x \cos x}{\sin^4 x + \cos^4 x} dx\]
If f is an integrable function, show that
\[\int\limits_{- a}^a f\left( x^2 \right) dx = 2 \int\limits_0^a f\left( x^2 \right) dx\]
\[\int\limits_0^1 \frac{x}{\left( 1 - x \right)^\frac{5}{4}} dx =\]
\[\int\limits_{- 1/2}^{1/2} \cos x \log\left( \frac{1 + x}{1 - x} \right) dx\]
If `intx^3/sqrt(1 + x^2) "d"x = "a"(1 + x^2)^(3/2) + "b"sqrt(1 + x^2) + "C"`, then ______.
