Advertisements
Advertisements
Question
Evaluate the following:
Γ(4)
Sum
Advertisements
Solution
Γ(4) = Γ(3 + 1)
= 3!
= 6
shaalaa.com
Definite Integrals
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
\[\int\limits_1^2 \frac{3x}{9 x^2 - 1} dx\]
If f is an integrable function, show that
\[\int\limits_{- a}^a f\left( x^2 \right) dx = 2 \int\limits_0^a f\left( x^2 \right) dx\]
\[\int\limits_0^1 \left( 3 x^2 + 5x \right) dx\]
\[\int\limits_0^3 \left( 2 x^2 + 3x + 5 \right) dx\]
\[\int\limits_0^1 2^{x - \left[ x \right]} dx\]
\[\int\limits_0^1 \sqrt{x \left( 1 - x \right)} dx\] equals
\[\int\limits_1^2 \frac{1}{x^2} e^{- 1/x} dx\]
Prove that `int_a^b ƒ ("x") d"x" = int_a^bƒ(a + b - "x") d"x" and "hence evaluate" int_(π/6)^(π/3) (d"x")/(1+sqrt(tan "x")`
Using second fundamental theorem, evaluate the following:
`int_1^"e" ("d"x)/(x(1 + logx)^3`
Choose the correct alternative:
`int_(-1)^1 x^3 "e"^(x^4) "d"x` is
